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denis-greek [22]
2 years ago
11

Tony is using the numbers 12 7 4 1 to make a new number?

Mathematics
1 answer:
galben [10]2 years ago
3 0

Step-by-step explanation:

Given:

To find:

Solution:

(multiplication of digits give a larger number compared to addition, subtraction and division)

= (12 × 7) × (4 + 1)

∴ The biggest number Tony can make is 420.

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Wyatt owns a new store on the boardwalk by the beach. He plans to sell beach balls in his store. Each one costs him $4.95. He wa
KonstantinChe [14]

Wyatt should charge $9.26 before 8% sales tax  if he does not want customers to pay more than $10.00

They will actually be charged $10 exactly.

9.26*.08= .74

.74+9.26= 10

4 0
2 years ago
What would be the solution to the inequality? x-20<100
BlackZzzverrR [31]

Answer:

the answer would be anything between 0-119 because any of these numbers minus 20 is still less than 100

tell me if this helped

4 0
3 years ago
Read 2 more answers
Police Chase: A speeder traveling 40 miles per hour (in a 25 mph zone) passes a stopped police car which immediately takes off a
zubka84 [21]

Answer:

a. 18.34 s b. 327.92 m

Step-by-step explanation:

a. How long before the police car catches the speeder who continued traveling at 40 miles/hour

The acceleration of the car a in 10 s from 0 to 55 mi/h is a = (v - u)/t where u = initial velocity = 0 m/s, v = final velocity = 55 mi/h = 55 × 1609 m/3600 s = 24.58 m/s and t = time = 10 s.

So, a =  (v - u)/t =  (24.58 m/s - 0 m/s)/10 s = 24.58 m/s ÷ 10 s = 2.458 m/s².

The distance moved by the police car in 10 s is gotten from

s = ut + 1/2at² where u = initial velocity of police car = 0 m/s, a = acceleration = 2.458 m/s² and t = time = 10 s.

s = 0 m/s × 10 s + 1/2 × 2.458 m/s² (10)²

s = 0 m + 1/2 × 2.458 m/s² × 100 s²

s = 122.9 m

The distance moved when the police car is driving at 55 mi/h is s' = 24.58 t where t = driving time after attaining 55 mi/h

The total distance moved by the police car is thus S = s + s' = 122.9 + 24.58t

The total distance moved by the speeder is S' = 40t' mi = (40 × 1609 m/3600 s)t' =  17.88t' m where t' = time taken for police to catch up with speeder.

Since both distances are the same,

S' = S

17.88t' = 122.9 + 24.58t

Also, the time  taken for the police car to catch up with the speeder, t' = time taken for car to accelerate to 55 mi/h + rest of time taken for police car to catch up with speed, t

t' = 10 + t

So, substituting t' into the equation, we have

17.88t' = 122.9 + 24.58t

17.88(10 + t) = 122.9 + 24.58t

178.8 + 17.88t = 122.9 + 24.58t

17.88t - 24.58t = 122.9 - 178.8

-6.7t = -55.9

t = -55.9/-6.7

t = 8.34 s

So, t' = 10 + t

t' = 10 + 8.34

t' = 18.34 s

So, it will take 18.34 s before the police car catches the speeder who continued traveling at 40 miles/hour

b. how far before the police car catches the speeder who continued traveling at 40 miles/hour

Since the distance moved by the police car also equals the distance moved by the speeder, how far the police car will move before he catches the speeder is given by S' = 17.88t' = 17.88 × 18.34 s = 327.92 m

4 0
2 years ago
Look at the division problem
Troyanec [42]

Answer: 3

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Step-by-step explanation: because of the decimal you have to place a zero regardless and the other 2 zeros you can’t do anything with them. Hope this helps!

8 0
3 years ago
11x + 6y = 6 then graph the equation ​
maw [93]

Answer:

Step-by-step explanation:

Use the intercept method of graphing a straight line:

Let x = 0.  We get y = 1.  This is the y-intercept (0, 1).

Let y = 0.  We get x = 6/11.  This is the x-intercept (6/11, 0).

Plot both points and then draw a straight line through them.

6 0
3 years ago
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