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Nady [450]
4 years ago
12

A rock is thrown vertically upward from the origin of a reference frame. The rock reaches the peak of its trajectory and then it

returns back to the origin where it comes to rest. Using the upward direction as positive, select True or False for the following statements. False The acceleration of the rock is negative throughout the whole motion. True The position of the rock is positive or zero throughout the whole motion. False The velocity of the rock is positive throughout the whole motion. False The acceleration of the rock is zero at the peak of the trajectory
Physics
1 answer:
Tema [17]4 years ago
6 0

Answer:

The acceleration of the rock is negative throughout the whole motion. (TRUE)

The acceleration of the rock is zero at the peak of the trajectory (FALSE)

The velocity of the rock is positive throughout the whole motion (FALSE)

The position of the rock is positive or zero throughout the whole motion (TRUE)

The velocity of the rock is positive throughout the whole motion (FALSE)

Explanation:

1)The acceleration of the rock is negative throughout the whole motion. (TRUE)

Using the upward direction as positive

Then, The acceleration of the rock is negative throughout the whole motion.

2)The acceleration of the rock is zero at the peak of the trajectory.(FALSE)

Only the velocity can be zero at the peak the trajectory, the acceleration is not zero

3)The velocity of the rock is positive throughout the whole motion (FALSE)

Using the upward direction as positive, The velocity of the rock is only positive when going in upward direction and vice versa

4)The position of the rock is positive or zero throughout the whole motion (TRUE)

When the rock get down it will have a zero position, then when it get to the peak it will have positive position

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Answer:

Incomplete question

This is the completed question

If the resistor in the circuit had a larger resistance then the current would be then have to be proportionally smaller. Because the batteries each give off 1.5 volts then the current would have to be the variable that would change. What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the current? What would happen to the resistor?

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V=iR

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