Answer:
point slope form: y-3=(x+2)
slope-intercept form: y=x+
Step-by-step explanation:
so to find point-slope form, you first have to find the slope of the line
--slope ==
(you have to use the two points shown: (-2,3) and (3,0) to plug in for y1, y2, x1, and x2 to find the slope.)
so your slope is .
Now all you have to do is use one of the points (-2,3) to sub in for y1 and x1 in the point-slope form equation.
Therefore, you get y-3=(x+2) for point-slope form.
Now for slope-intercept form, you already have the slope because you found it to complete the equation for point slope form
slope =
Now slope intercept form is y=mx+b, where m is the slope and b is the y-intercept.
So, far we have y=x+b
the easiet point to use for the x and y values is (3,0)
so, lets substitute: 0=(3)+b, which becomes 0=
+b
add to both sides to get b=
Now you have both the slope and the y-intercept so you can now write the line in slope-intercept form.
You get .