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IRISSAK [1]
3 years ago
14

For the reaction 2SO2+O2 ---> 2SO3 write the forward and reverse reactions

Chemistry
1 answer:
cupoosta [38]3 years ago
3 0
2SO2(g) + O2(g) ---> 2SO3(g) • 2SO2(g) + O2(g) <--- 2SO3(g) • 2SO2(g) + O2(g) <---> 2SO3(g) • 2SO2(g) + O2(g) <--->> 2SO3(g) • Note: The rate of change reaches an equilibrium. The concentration of reactants and products is not equa
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Fudgin [204]

Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

P x V = k

Therefore, for this problem the step by step explanation is:

P_{1} xV_{1} = P_{2} xV_{2}

Clearing P2 and replacing

P_{2}= \frac{P_{1} xV_{1}}{V_{2} } = \frac{4atmx3L}{20L} = 0.6atm

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