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brilliants [131]
3 years ago
11

What term best describes the type of reaction that happens when a single element reacts with a molecule or compound, producing a

new single element and a new molecule or compound?
A. an isolation reaction

B. a single combustion reaction

C. a single replacement reaction

D. a double replacement reaction
Chemistry
2 answers:
noname [10]3 years ago
7 0

Answer: a single replacement reaction

Explanation:

Combustion is a type of chemical reaction in which fuel is reacted with oxygen to form carbon dioxide and water.

Example:  

C_6H_{12}O_6+O_2 \rightarrow CO_2+H_2O

Double displacement reaction is one in which exchange of ions take place.  

Example: 2NaOH(aq)+(NH_4)_2SO_4(aq)\rightarrow 2NH_4OH(aq)+Na_2SO_4(aq)

Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

Example: Zn+CuCl_2\rightarrow ZnCl_2+Cu

Here Zinc an element reacts with the compound copper chloride  to form new compound zinc chloride and new element copper.

gogolik [260]3 years ago
5 0

The answer is

C. A single replacement reaction (acid reactions)

An example would be the reaction between simple metal Potassium (K) and Water (H2O), resulting in a much solid compound called Potassium Hydroxide (KOH) and hydrogen gas is set free.

K+H2O --> KOH

You might be interested in
Consider the reaction of solid aluminum iodide and potassium metal to form solid potassium iodide and aluminum metal.The balance
ratelena [41]

Answer:

674.26 g of AlI₃

Explanation:

We'll begin by calculating the theoretical yield of aluminum (Al). This can be obtained as follow:

Percentage yield of Al = 67.8%

Actual yield of Al = 30.25 g

Theoretical yield of Al =?

Percentage yield = Actual yield /Theoretical yield × 100/

67.8% = 30.25 / Theoretical yield

67.8 / 100 = 30.25 / Theoretical yield

0.678 = 30.25 / Theoretical yield

Cross multiply

0.678 × Theoretical yield = 30.25

Divide both side by 0.678

Theoretical yield = 30.25 / 0.678

Theoretical yield of Al = 44.62 g

Next, we shall determine the mass of AlI₃ that reacted and the mass of Al produced from the balanced equation. This can be obtained as follow:

AlI₃(s) + 3K(s) → 3KI(s) + Al(s)

Molar mass of AlI₃ = 27 + (3×127)

= 27 + 381 = 408 g/mol

Mass of AlI₃ from the balanced equation = 1 × 408 = 408 g

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 1 × 27 = 27 g

Summary:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Finally, we shall determine the mass of

AlI₃ required to produce 44.62 g of Al. This can be obtained as follow:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Therefore, Xg of AlI₃ will react to produce 44.62 g of Al i.e

Xg of AlI₃ = (408 × 44.62)/27

Xg of AlI₃ = 674.26 g

Thus, 674.26 g of AlI₃ is needed for the reaction.

8 0
3 years ago
HELP!! BRAINLIEST 50 POINTS
zhenek [66]

Answer:

The given equation obey the law of conservation of mass.

Explanation:

Chemical equation:

2LiOH + CO₂  →   Li₂CO₃ + H₂O

There are equal number of atoms of oxygen, hydrogen and lithium on both side of equation so it obey the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

2LiOH                +            CO₂         →         Li₂CO₃           +                    H₂O

2(6.941 + 16 + 1)  +          12+32                   6.941×2 + 12 + 3×16     +       18

47.882 + 44                                                  13.882 +12+48   +   18

91.882 g                                                                91.882 g

The mass of reactants and product are equal.

6 0
3 years ago
2HCl+Ca(OH)2⟶CaCl2+2H2O
RUDIKE [14]
Isn’t it just 3 mols?
5 0
3 years ago
What observation would you look for to tell if a reaction was endothermic?
horsena [70]

Exothermic reactions release heat into their surroundings and endothermic reactions absorb heat and are cool. I believe the correct answer is D.

5 0
2 years ago
A eudiometer contains a 65.0 ml sample of a gas collected
SCORPION-xisa [38]

Answer:

53.1 mL

Explanation:

Let's assume an ideal gas, and at the Standard Temperature and Pressure are equal to 273 K and 101.325 kPa.

For the ideal gas law:

P1*V1/T1 = P2*V2/T2

Where P is the pressure, V is the volume, T is temperature, 1 is the initial state and 2 the final state.

At the eudiometer, there is a mixture between the gas and the water vapor, thus, the total pressure is the sum of the partial pressure of the components. The pressure of the gas is:

P1 = 92.5 - 2.8 = 89.7 kPa

T1 = 23°C + 273 = 296 K

89.7*65/296 = 101.325*V2/273

101.325V2 = 5377.45

V2 = 53.1 mL

6 0
3 years ago
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