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BaLLatris [955]
3 years ago
8

Convert 550 torr into SI units.

Chemistry
1 answer:
Dovator [93]3 years ago
6 0

Answer:

73,326 Pa

Explanation:

73,326 Pa

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How many molecules of CO2 will be produced by the decomposition
34kurt

Answer:

2.99×10²⁵ molecules of CO₂ are produced

Explanation:

Decomposition reaction is:

Ca(HCO₃)₂ => CaO(s) + 2CO₂(g) + H₂O(g)

Ratio is 1:2. Let's make a rule of three:

1 mol of bicarbonate can produce 2 moles of CO₂

Therefore, 24.9 moles of bicarbonate may produce, 49.8 moles (24.9 .2 )/1

Let's determine the number of molecules

1 mol has 6.02×10²³ molecules

49.8 moles must have (49.8 . 6.02×10²³) / 1 = 2.99×10²⁵ molecules

4 0
3 years ago
A 62.6-gram piece of heated limestone is placed into 75.0 grams of water at 23.1°C. The limestone and the water come to a final
alekssr [168]

Answer:

208.7°C was the initial temperature of the limestone.

Explanation:

Heat lost by limestone will be equal to heat gained by the water

-Q_1=Q_2

Mass of limestone = m_1=62.6 g

Specific heat capacity of limestone = c_1=0.921 J/g^oC

Initial temperature of the limestone = T_1=?

Final temperature = T_2=T =  51.9°C

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.0 g

Specific heat capacity of water= c_2=4.186 J/g^oC

Initial temperature of the water = T_3=23.1^oC

Final temperature of water = T_2=T =  51.9°C

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(62.6 g\times 0.921 J/g^oC\times (51.9^oC-T_1))=75.0 g\times 4.186 J/g^oC\times (51.9^oC-23.1^oC)

T_1=208.7^oC

208.7°C was the initial temperature of the limestone.

7 0
3 years ago
Asparagine is a polar amino acid shown here at ph 7 what is the maximum
KonstantinChe [14]
Maximum number of water molcules which can take part in forming hydrogen bonding interaction with asparagine are 13. Following structure shows the interactions. Lone pair of electrons act as hydrogen bond acceptors and hydrogen atoms attached to heteroatoms acts as hydrogen bond donors.

3 0
3 years ago
We dissolve 93 grams of sodium sulfate (Na2SO4) in 20 grams of water. What is the percent by mass of sodium sulfate in this solu
dlinn [17]
It should be for the total solution of 93 plus 20 grams which is 113 grams so 93 divided by 113 grams comes to 82.3% sodium sulfate and this can be checked by multiplying 113 grams by 0.823 which results in 93 grams of sodium sulphate. 
4 0
4 years ago
The area that includes everything between the cell membrane and the nucleus of a cell is called the
kolbaska11 [484]

Answer:

Cytoplasm.

Explanation:

Please mark as Brainliest! :)

8 0
3 years ago
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