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Maslowich
3 years ago
13

How is sonoluminescence similar to what we see in fireworks?​

Chemistry
1 answer:
aalyn [17]3 years ago
7 0

Answer:

Explanation:

Sonoluminescence is a phenomenon in which small gas bubbles burst to produce light when intense sound wave is introduced. Thus, it can be said that sound energy is converted to light energy here. This is similar to the process of how fire crackers work except that sonoluminescence occurs in a liquid medium while firecrackers work in solid media. In firecrackers, when the tip is lit with fire, the initial explosion is caused by the expansion of some nitrogen and carbon present in some constituent compounds, this explosion produces heat which causes some other constituent chemicals in the firecracker to quickly react and produce light. Thus, this can also be said to convert sound energy to light energy and are thus similar to what occurs in sonoluminescence.

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Name the type of organic compound from each description of the functional group: (b) group that is not polar and has a double bo
krek1111 [17]

Some of the crucial functional groups in organic compounds are the hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl groups. The formation of molecules including DNA, proteins, carbohydrates, and lipids depends heavily on these groups.

<h3>What is Function Group ?</h3>

In organic chemistry, a functional group is a collection of atoms within molecules that interact to cause predictable reactions. Functional groups include the hydroxyl, ketone, amine, and ether groups, for instance.

(b) Most double bonds, such those found in alkenes, are formed when two carbon atoms are present. In a carbonyl group, for instance, where a carbon atom and an oxygen atom are together, there are several double bonds connecting the two separate components. Sulfoxides (S=O), imines (C=N), and azo compounds (N=N) also include common double bonds.

To know more about Functional Group please click here : brainly.com/question/493841

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8 0
2 years ago
What is the percent composition by mass of oxygen in Ca(NO3)2 (gram-formula= 164 g/mol)?
Neko [114]
To find this, we will use this formula:

Molar mass of element
------------------------------------ x 100
Molar mass of compound

So, first lets calculate the mass of the compound as a whole. We use the atomic masses on the periodic table to determine this.

Ca: 40.078 g/mol
N2 (there is two nitrogens): 28.014 g/mol
O6 (there are six nitrogens: 3 times 2): 95.994 g/mol

When we add all of those numbers up together, we get 164.086. That is the molar mass for the whole compound. However, we are trying to figure out what percent of the compound oxygen makes up. From the molar mass, we know that 95.994 of the 164.086 is oxygen. Lets plug those numbers into our equation!

95.994
-----------
164.086

When we divide those two numbers, we get .585. When we multiply that by 100, we get 58.5.

So, the percent compostition of oxygen in Ca(NO3)2, or, calcium nitrate, is 58.5%.
5 0
3 years ago
Who is interested in a middle schooler?
belka [17]

Answer:

I think that middle school teachers are interested in teaching middle schoolers.

6 0
3 years ago
Describe the valence electrons in nitrogen and how it could bond to other atoms.
Trava [24]

Answer:

Each nitrogen molecule consists of two atoms of nitrogen that are bonded by a triple covalent bond. This is a direct consequence of the fact that each nitrogen atom has 5 valence electrons. Each atom can thus complete its octet by sharing three electrons.

Explanation:

Sorry i had to look it up i didn't know this answer

Please mark brainliest:)

6 0
3 years ago
C5H12 + O2 = CO2 + H2O
Lady_Fox [76]

Answer: 241.6 grams of CO2

Explanation: you take 84.3 grams C5H12 and divide it by 72.15 grams of C5H12(which is the molar mass) you take that answer and calculate the mols of CO2 by multiplying the 1.168 you got before and multiply it by 5. You take the answer you get from that and multiply it by the molar mass of CO2 and get the theoretical yield and then you just plug it in. 94= (x/257.02)x100 and solve to find x which is the actual yield.

3 0
3 years ago
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