There are two N≡N bonds and three H–H bonds are in reactants.
Given:
The reaction between nitrogen gas and hydrogen gas.

To find:
Bonds on the reactant side
Solution:

Reactants in the reaction = 
The bond between nitrogen atoms in single
molecule = N≡N (triple bond)
Then in two
molecules = 2 N≡N (triple bonds)
The bond between hydrogen atoms in single
molecule = H-H (single bond)
Then in three
molecules = 3 H-H (single bonds)
Product in the reaction =
The bonds between nitrogen and hydrogen atoms in single
molecule = 3 N-H (single bond)
Then in two
molecules = 6 N-H (single bonds)
So, there are two N≡N bonds and three H–H bonds are in reactants.
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Answer:
Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure, as the potential energy due to intermolecular forces becomes less significant compared with the particles' kinetic energy, and the size of the molecules becomes less significant compared to the empty space between them.
Explanation:
Answer:
11
Explanation:
An atomic number of 11 means this atom will have 11 protons. A mass number of 23 means 23 - 11 this atom will have 12 neutrons. Since this atom is neutral the positive protons must be equal to the negative electrons. This atom will have 11 electrons