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mel-nik [20]
3 years ago
11

Suppose that NaCl is added to hexane (C6H14) instead of water. Which of the following intermolecular forces will exist in the sy

stem?
Check all that apply.

Ion-dipole force between Na+ ions and a hexane molecule
Ion-ion force between Na+ and Cl− ions
Dipole-dipole force between two hexane molecules
Hydrogen bonding between Na+ ions and a hexane molecule
London dispersion force between two hexane molecules
Chemistry
2 answers:
svet-max [94.6K]3 years ago
5 0

Answer:

Ion-ion force between Na+ and Cl− ions

London dispersion force between two hexane molecules

Explanation:

"Ion-dipole force between Na+ ions and a hexane molecule " does not exist since hexane has only non-polar bonds and therefore no dipole.

"Ion-ion force between Na+ and Cl− ions " exists since both are ions.

"Dipole-dipole force between two hexane molecules " does not exist since hexane molecules do not have a dipole.

"Hydrogen bonding between Na+ ions and a hexane molecule " does not exist since the hydrogen in the hydrogen bond must be bonded directly to an electronegative atom, which hexane does not have since it is a hydrocarbon.

"London dispersion force between two hexane molecules" exist since hexane is a molecular compound.

aivan3 [116]3 years ago
5 0

Answer:

Ion-ion force between Na⁺ and Cl⁻ ions.

London dispersion force between two hexane molecules.

Explanation:

<em>Suppose that NaCl is added to hexane (C₆H₁₄) instead of water. Which of the following intermolecular forces will exist in the system? </em>

<em>Check all that apply. </em>

  • <em>Ion-dipole force between Na⁺ ions and a hexane molecule.</em> NO. Hexane is nonpolar so it can interact through ion-dipole forces.
  • <em>Ion-ion force between Na⁺ and Cl⁻ ions.</em> YES. Na⁺ is a cation (positive ion) and interacts with the anion (negative ion) Cl⁻ through ion-ion forces.
  • <em>Dipole-dipole force between two hexane molecules.</em> NO. Since hexane molecules are not dipoles, they do not show dipole-dipole interaction.
  • <em>Hydrogen bonding between Na⁺ ions and a hexane molecule.</em> NO. Hydrogen bonding requires H bonded to a very electronegative atom, such as N, O or F, which does not happen in hexane.
  • <em>London dispersion force between two hexane molecules.</em> YES. The kind of interaction between nonpolar molecules is London dispersion force.
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Explanation:

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This cycle involves the fusion of four protons with carbon (_{6}^{12}\textrm{C}), nitrogen isotope (_{7}^{13}\textrm{N}), and oxygen isotope (_{8}^{15}\textrm{O}), to give an alpha particle and two electron neutrinos and positrons.

The reaction involves the regeneration of carbon (_{6}^{12}\textrm{C}) nucleus in the last step.

_{6}^{12}\textrm{C} → _{7}^{13}\textrm{N} → _{6}^{13}\textrm{C} → _{7}^{14}\textrm{N} → _{8}^{15}\textrm{O} → _{7}^{15}\textrm{N} → _{6}^{12}\textrm{C}

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3 years ago
calculate the mass of 120cc nitrogen present at STP. how many number of molecules are present in it?​
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Answer:

0.15008\ \text{g}

3.23\times 10^{21}

Explanation:

1 mol of nitrogen at STP = 22.4 L = 22400 cc

n = Mol of N_2 = \dfrac{120}{22400}=0.00536\ \text{mol}

M = Molar mass of N_2 = 28\ \text{g/mol}

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

Mass of N_2 is

m=nM\\\Rightarrow m=0.00536\times 28\\\Rightarrow m=0.15008\ \text{g}

Mass of the nitrogen is 0.15008\ \text{g}

Number of molecules is given by

nN_A=0.00536\times 6.022\times 10^{23}=3.23\times 10^{21}\ \text{molecules}

The number of molecules present in it are 3.23\times 10^{21}

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Explanation:

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\large\boxed{\text{28 mol of O$_{2}$}}

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