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Nata [24]
3 years ago
12

HELP: Cho charges $1500 to build a small deck and $2500 to build a large deck. During the spring and summer, she built 5 more sm

all decks than large decks.
If she earned $23,500 how many of each type of deck did she build?
Mathematics
1 answer:
Ludmilka [50]3 years ago
7 0

Answer:

if she build x numbers of large decks, therefore small decks would be (x + 5)

1500*(x+5)+2500x   =23500

1500x+7500+2500x=23500

4000x+7500             =23500

                        4000x=23500-7500

                         4000x=16000

                                  x=4

4+5=9

cho built 4 large decks and 9 small decks

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-2/3f=9.2<br> -1/8n = -2/7 <br> 12/20n = -36/44<br> -64.5g = -25.8 <br> -15/28 = -9/10
user100 [1]

Step-by-step explanation:

-2/3f =9.2

cross multiply

27,6= -2f

divide both sides by 2

f = - 13.8

-1/8n = -2/7

cross multiply

-16 = -7n

divide

n = 2.29

12/20n = -36/44

cross multiply

528 = - 720n

divide

n= -0.733

-64.5g = -25.8

divide both sides by -64.5

g = -0.4

the last one has no variable

5 0
3 years ago
Helllpppppppppppppppp asap 22 pts
Rama09 [41]
<span>The image gives the interval of the values of a data set. It is the difference between the highest number and the lowest number in a dataset. It summarizes all the values of a data with a single number. (3). Since the data has no outlier, the mean will be the best measure of central tendency to describe the score.</span>
5 0
3 years ago
The temperature, t, in degrees Fahrenheit, can be found by counting the number of cricket chirps, c, heard in 14 seconds and the
AleksandrR [38]

The graph is continuous.A viable solution is (10, 50) at the function t = c + 40.

The complete question is given below:-

The temperature, t, in degrees Fahrenheit, can be found by counting the number of cricket chirps, c, heard in 14 seconds and then adding 40. The equation t = c + 40 models the relationship between the temperature and the number of cricket chirps. What is true about the graph that represents this real-world scenario? Check all that apply.

<h3>What is a graph?</h3>

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

The graph is continuous.

A viable solution is (10, 50).

t = c + 40

The given equation is

t = c + 40

This equation models the relationship between the temperature and the number of cricket chirps.

Where is the temperature in degrees Fahrenheit and is the number of cricket chirps heard in 14 seconds?

According to the problem, the temperature can be found by counting the number of cricket chirps heard in 14 seconds and then adding 40.

Now, the choices to this question are

The graph is continuous.

All values of t must be positive.

A viable solution is (–2, 38).

A viable solution is (0.5, 40.5).

A viable solution is (10, 50).

The graph of the given equation is attached, it shows the linear relationship between both variables.

Notice that the graph is continuous, it doesn't have any restriction, nor "emptiness" at certain values.

Observe that the remaining choices are all solutions to the equation, but not all of them are viable because the number of cricket chirps must be positive and integer because we can't hear the sound of 0.5 cricket.

Therefore, the last choice is viable (10, 50).

To know more about graphs follow

brainly.com/question/25020119

#SPJ1

6 0
1 year ago
Question 2: What is the volume of this prism?
laiz [17]

Answer:

42 cubic units

Step-by-step explanation:

2x3x7

6 0
2 years ago
I need help with this question.
Papessa [141]

Answer:

It's A, c =2.5d

Step-by-step explanation:

When it comes to problems like this, I usually look through the answers and try to plug in the numbers until I get the right equation that fits with the graph.

2.5(5) = 12.5

2.5(10)= 25

2.5(15)= 37.5

2.5(20) = 50

2.5(25) = 62.5

If you compare this to the graph, you'll notice the solutions are the same as the Total Cost (c). That's because c= 2.5d is the right equation for this graph. (Sorry if my explanation is confusing)

5 0
2 years ago
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