A sample of sugar (C12H22O11) contains
1 answer:
Answer: 0.25 mol
Explanation:
Use the formula n=N/NA
n= number of mols
N = number of particles
Nᵃ = Avogadros constant = 6.02 x
So, n=
The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.
Hope this helped :)
You might be interested in
Answer:
hey love! what is the question??
Answer:
i would try B
Explanation:
Answer:
6s
Explanation:
Barium is in group 2 of the s block and is in period 6.
Can u explain it more plz.