A sample of sugar (C12H22O11) contains

Chemistry

1 answer:

Oduvanchick [21]3 years ago

5 0

Answer: 0.25 mol

Explanation:

Use the formula n=N/NA

n= number of mols

N = number of particles

Nᵃ = Avogadros constant = 6.02 x

So, n=

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

Hope this helped :)

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