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kirza4 [7]
3 years ago
6

Enter the coefficients that balance the tarnishing

Chemistry
1 answer:
olga55 [171]3 years ago
7 0

Answer:

2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)

Explanation:

Step 1: Data given

Ag(s) + H2S(g) → Ag,S(s) + H2(g)

Ag has and oxidation number of +1

S has an oxidation number of -2

H has an oxidation number of +1

Step 2: The balanced equation

Ag+ + 2H+ + S^2- →

The silver ion and the sulfur ion will bind, but we need 2 silver atoms to bind with 1 sulfur atom.

2 H- atoms will appear as H2.

The balanced equation is:

2Ag+ + 2H+ +S^2- → Ag2S + H2

2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)

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When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 22.8g of carbon were burned in the presence of
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Answer:

83.6 g  

Explanation:

The limiting reactant is carbon and oxygen is in excess.

C + O₂ ⟶ CO₂

Data:

                  Mass of C = 22.8 g

                 Mass of O₂ = 78.0 g

Mass of unreacted O₂ =  17.2 g

Calculations:

          Mass of O₂ reacted = 78.0 g  -  17.2 g = 60.8 g

Mass of reactants (C + O₂) = 22.8 g + 60.8 g = 83.6 g

According to the Law of Conservation of Mass, the mass of the product (CO₂) equals the sum of the masses of the reactants.

The mass of CO₂ is 83.6 g.

3 0
3 years ago
7. Assume that you have collected 867 L of nitrogen gas at STP. What is the mass of the nitrogen gas?
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Answer:

1083.6 g

Explanation:

At STP, 1 mol of any given mass will occupy 22.4 L.

With the information above in mind we can<u> calculate how many moles of nitrogen gas (N₂) are there in 867 L</u>:

  • 867 L ÷ 22.4 L/mol = 38.7 mol

Finally we convert 38.7 moles of N₂ into grams, using its molar mass:

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Please upload a photo of your question!
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Express 727,000 in scientific noation
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727,000 in scientific notation is written as 7.27 * 10^5

The decimal or whole number must be between 1 and 10. Then, what I do, is count the amount it takes me to get to 7.27, which, in this case, is 5

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3 years ago
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