3 years ago

Jadon wants to buy a new game system that costs

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

7 0

Answer:

try adding togther

Step-by-step explanation:

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A researcher wishes to estimate, with 9090% confidence, the proportion of adults who have high-speed Internet access. Her es

Sunny_sXe [5.5K]

Answer: a) Required minimum sample size= 219

b) Required minimum sample size= 271

Step-by-step explanation:

As per given , we have

Margin of error : E= 5% =0.05

Critical z-value for 90% confidence interval : $z_{\alpha/2}=1.645$

a) Prior estimate of true proportion: p=28%=0.28

Formula to find the sample size :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.28(1-0.28)(\dfrac{1.645}{0.05})^2\\\\=218.213856\approx219$

Required minimum sample size= 219

b) If no estimate of true proportion is given , then we assume p= 0.5

Formula to find the sample size :-

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.645}{0.05})^2\\\\=270.6025\approx271$

Required minimum sample size= 271

8 0

3 years ago

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nirvana33 [79]

Answer:

(16√75)/(5√12) = 8

Step-by-step explanation:

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3 years ago

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Math!! Who knows answers???

Yanka [14]

option C for Qno10

and option a for Qno 9

6 0

3 years ago

Simplify the expression:<br> 5m^(n+1) times 3m^(2n)

Karolina [17]

Answer:

15m^3n + 1

Step-by-step explanation:

i hope this helps

3 0

2 years ago

if 6th term of an ap is -10 and 10 th term is -26 then find thr 15 term plzzzzzzzzzzzzzzzzzzzzzzz answer i will give whatever y

Rudik [331]

Answer:

-46

Step-by-step explanation:

We need to find the common difference of this arithmetic sequence:

$\frac{-26-(-10)}{10-6} =\frac{-16}{4} =-4$

So, the common difference d = -4. We can now write the equation:

$a_n=a_1+d(n-1)$

$a_{15}=a_6+d(15-6)=-10-4(9)=-10-36=-46$

So, the 15th term is -46.

Hope this helps!

5 0

3 years ago

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