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Sergeeva-Olga [200]
3 years ago
12

A particle moves in a straight line. Its speed(v)

Physics
1 answer:
Alina [70]3 years ago
3 0

Answer:

6v_0

Explanation:

The speed of the particle increases linearly with time, so we can write it as

v(t) = kt+v_0

where k is the a certain constant of proportionality and v_0 is the initial speed.

We also know that at t = 4 s, the speed is v=2v_0, so we can use this information to find k:

v(4) = 4k+v_0 = 2v_0 \rightarrow k = \frac{v_0}{4}

So the complete expression of v(t) is

v(t) = \frac{v_0}{4}t+v_0 = v_0 (\frac{t}{4}+1)

Now we integrate the quantity v(t), and we find:

\int {v(t)} \, dt =\int (\frac{v_0}{4}t+v_0) \, dt =\frac{v_0}{8}t^2 + v_0 t

Substituting the limit of integration t = 4, we find:

\frac{v_0}{8}4^2 + 4v_0 =2v_0+4v_0 = 6v_0

And substituting t = 0, we find 0. So, the result of the integration from 0 to 4 is

6v_0

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Butoxors [25]

Answer:

The value is v  =  2.999 *10^{8} \  m/s

Explanation:

From the question we are told that

   The time taken to travel to the planet from earth is t = 189 \ light-years

    The  time to be spent on the ship is  t_{s} =  12 \  years

Generally speed can be obtained using the mathematical relation represented below

       t_s  =  2 * t *  \sqrt{1 -  \frac{v^2}{c^2 } }

The 2 in the equation show that the trip is a round trip i.e going and coming back

=>    12 =  2 * 189 *  \sqrt{1 -  \frac{v^2}{(3.0*10^{8})^2 } }

=>     v  =  2.999 *10^{8} \  m/s

5 0
3 years ago
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noname [10]

Answer:

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Explanation:

3 0
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mr_godi [17]

Answer:

The minimum thickness = 83.92 nm

Explanation:

The relation between the wavelength in a particular medium and refractive index \lambda_n = \frac{ \lambda }{n}

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\lambda = wavelength of the light in vacuum

n = refractive index of medium with respect to vacuum

For one phase change :

2t = \frac{\lambda_n}{2}\\\\where \ \lambda_n = \frac{\lambda}{n}\\\\Then \ \\\\2t = \frac{\lambda}{2n}\\\\t = \frac{\lambda_n}{4n}

Replacing 1.43 for n and 480 nm for λ; we have:

t = \frac{480}{4(1.43)}

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Thus; the minimum thickness = 83.92 nm

4 0
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Misha Larkins [42]

Answer:

c. initial (x and y)

Explanation:

When a projectile is launched at a velocity with a launch angle, to solve it, we must first resolve the initial velocity into the x and y components. To do this will mean we have to treat it like a triangle due to the launch angle and the direction of the projectile.

Therefore, we will have to make use of trigonometric ratios which is also known by the mnemonic "SOH CAH TOA"

Thus, this method resolves the initial x and y velocities.

3 0
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Kisachek [45]

Answer:

triangulation

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using your compass

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