8(3)(4) = 96
96-16(5)= 16
16- 3^2 = 9.
9
Answer:
B and the first d and second one.
Step-by-step explanation:
The age is a big factor and b can showing the preference per age
Answer:
since -3.73 is less than 1.645, we reject H₀.
Therefore this indicate that the proposed warranty should be modified
Step-by-step explanation:
Given that the data in the question;
p" = 13/20 = 0.65
Now the test hypothesis;
H₀ : p = 0.9
Hₐ : p < 0.9
Now lets determine the test statistic;
Z = (p" - p ) / √[p×(1-p)/n]
= (0.65 - 0.9) /√[0.9 × (1 - 0.9) / 20]
= -0.25 / √[0.9 × 0.1 / 20 ]
= -0.25 / √0.0045
= -0.25 / 0.067
= - 3.73
Now given that a = 0.05,
the critical value is Z(0.05) = 1.645 (form standard normal table)
Now since -3.73 is less than 1.645, we reject H₀.
Therefore this indicate that the proposed warranty should be modified
Answer:
1.thursday
his expenses was p26.85
2.monday he spent p40.8
3.18.90+23.15+11.80+16.35+9.20=approximately p55.6×30 days=p1,668
4.693.80-1,668
so he savings is completely enough
A. 2x+y=25; x+y=20
x represents cheese wafers and y represents chocolate wafers.
B. I will choose elimination since there is y and y. I can multiply one equation by -1 to get y and -y, which cancels out.
2x+y=25
-x-y=-20
Add equations
x=5
Plug x in
5+y=20
y=15
Final answer: 5 cheese wafers, 15 chocolate wafers
