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3 years ago

15

Find the slope of the lined graph below

1 answer:

Nezavi [6.7K]3 years ago

7 0

The answer to your problem will be negative slope you’ll thank me later

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Given the points A(-10, -4) and B(14, 4), find the coordinates of the point P on the directed line segment AB that partitions AB

anastassius [24]

Answer:

P(5, 1)

Step-by-step explanation:

Segment AB is to be partitioned in a ratio of 5:3. That means the ratio of the lengths of AP to PB is 5:3. We need to find the ratio of the lengths of AP to AB.

AP/PB = 5/3

By algebra:

PB/AP = 3/5

By a rule of proportions:

(PB + AP)/AP = (3 + 5)/5

PB + AP = AP + PB = AB

AB/AP = 8/5

AP/AB = 5/8

The first part of the segment is 5/8 of the length of the segment, and the second part of the segment has length of 3/8 of the length of segment AB.

Point P is located 5/8 of the distance from point A to point B. The x-coordinate of point P is 5/8 of the difference in x-coordinates added to the x-coordinate of point A. The y-coordinate of point P is 5/8 of the difference in y-coordinates added to the y-coordinate of point A.

x-coordinate:

difference in coordinates: |14 - (-10)| = |14 + 10| = 24

5/8 of 24 = 5/8 * 24 = 15

Add 15 to the x-coordinate of point A: -10 + 15 = 5

x-coordinate of point P: 5

y-coordinate:

difference in coordinates: |4 - (-4)| = |4 + 4| = 8

5/8 of 8 = 5/8 * 8 = 5

Add 5 to the y-coordinate of point A: -4 + 5 = 1

y-coordinate of point P: 1

Answer: P(5, 1)

3 0

3 years ago

How do I do this? Please provide steps.

matrenka [14]

Answer:

3/5

Step-by-step explanation:

Soh Cah Toa

In some trigonometry classes, this acronym is very important to solving questions like this.

Why?

It tells us the right triangle-definition of these trigonometry functions.

We have that cosine of an angle is equal to tge side that is adjacent to it over the hypotenuse.

So here we are asked to find cos(B).

Lets look at triangle respect to the angle B

The measurement of the side that is opposite is 64.

The measurement of the side that is adjacent is 48.

The measurement of the hypotenuse is 80.

So cos(B)=48/80.

Let's reduce. 48 and 80 have a common factor of 8 so divide numerator and dexter by 8. This gives us:

cos(B)=6/10.

One more step in reducing. Both factors are even so cos(B)=3/5.

6 0

3 years ago

An unknown number b is 10 more than an unknown number k. the number b is also k less than 8. the equations to find k and b are s

Dmitriy789 [7]

Just add the two equations together.
2b = 18
b = 18/2
b = 9

9 = k + 10
9 - 10 = k
k = - 1

6 0

3 years ago

Read 2 more answers

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

2 years ago

Can someone please helpppppppp

saw5 [17]

Answer:

first one

Step-by-step explanation:

hhhhjnbbbnhhh

8 0

3 years ago