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3 years ago

Find the slope of the lined graph below

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

7 0

The answer to your problem will be negative slope you’ll thank me later

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How to solve this and what’s the final answer

dolphi86 [110]

Answer:

729 m³

Step-by-step explanation:

Volume of a cube (or a rectangular prism) formula:

lwh

l is length

w is width

h is height

Here, the length, width, and height measures 9 m.

9 × 9 × 9 or 9³ = 729

6 0

4 years ago

Find the direvitive of <br>f(x)=3x(6x-5x^2)

Artyom0805 [142]

the answer to the problem y=−15x3+18x2

8 0

3 years ago

Evaluate f(x) = 5x2 - 4x - 9 for f(-2)

Svetllana [295]

Answer:

Step-by-step explanation:

5x^2 -4x -9

5(-2)^2 -4(-2) -9

-10^2 +8 -9

100-1

8 0

4 years ago

Question Help

vovikov84 [41]

Answer:

Step-by-step explanation:

6 0

3 years ago

Determine whether the three given points are collinear. (3, 2), (4, 6), (0, 8) True: they are collinear False: they are not coll

FinnZ [79.3K]

Answer:

They are not co-linear.

Step-by-step explanation:

For three point's to be co linear the slopes of the lines connecting them should be same

Mathematically we can write for $(x_{1},y_{1}),(x_{2},y_{2}),(x_{3},y_{3})$

to be co-linear we should have

$\frac{y_{3}-y_{2}}{x_{3}-x_{2}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{y_{3}-y_{1}}{x_{3}-x_{1}}$

Applying the given values we obtain

$\frac{y_{3}-y_{2}}{x_{3}-x_{2}}=\frac{8-6}{0-4}=-1/2\\\\\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{6-2}{4-3}=3\\\\\frac{y_{3}-y_{1}}{x_{3}-x_{1}}=\frac{8-2}{0-3}=-2$

As we can see the values are not equal thus the points are not co-linear.

6 0

3 years ago