Racket : 94
balls : 12.50
warm ups : 34
shorts : 19.95
shoes : 44.50
total with tax : 204.95 + .05(204.95) = 204.95 + 10.25 = 215.20
20 per lesson for 12 lessons : 20 * 12 = 240
12 miles 1 way....thats 24 miles round trip, at 0.42 per mile : 24(0.42) =
10.08.....lessons and mileage : 240 + 10.08 = 250.08
for a total of : 215.20 + 250.08 = 465.28 <==
A bag contains three red marbles, six blue marbles, and three yellow marbles.
therefore total no. of marbles = 3 + 6 + 3 = 12
total no. of red marble = 3
therefore probablity of selecting one red marble is 3/12 = 1/4
again total no. of blue marbles is 6
therefore probability of selecting one blue marble is 6/12 = 1/2
now total probability of selecting one red ball replacing it then selecting one blue marble is. 1/4 * 1/2 = 1/8
Answer:
Tauren has 78 keychains
James has 34 keychains
Marcus has 68 keychains
Yahya has 74 keychains
Step-by-step explanation:
I got this answer by doing this:
If Tauren has 78 keychains then its gonna be left like that.
If everybody else has an average of 68 keychains then divide 68 by 2 to get half of what marcus has which equals 34.
Then add the amount of James and marcus keychains which is 68 plus 34 which equals 102, the subtract the 28 because it says Yayha has 28 fewer keychains and that equals 74.
x^2 = 16/100
We must solve for x by taking the square root of both sides.
But imagine x^2 = 9. x = 3 is a solution because 3^2 = 9. But x = -3 is also a solution because (-3)^2 = 9. So we need to add the plus and minus sign to account for all of our solutions.
√x^2 = √(16/100)
We square root both sides to remove the exponent 2 on x. Then
x = ±√(16/100)
Then we have to use a Property of Radicals which is √(x/y) = √(x) / √(y).
Then the square root of 16 is 4 and the square root of 100 is 10. 4/10 is 2/5 simplified.
Area of the bases
<span>2π<span>r2</span>=2π∗784=1568π
</span>circumference of base
<span>2πr=56π
</span>extension of the height
<span>2πr∗h=56π∗48=2688π
</span>bases plus none base surface is total surface
<span><span>1568π+2688π=4256π</span></span>
