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Nataliya [291]
3 years ago
7

Karen owns a seafood restaurant. She orders trout from an online retailer.

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

Answer: 30x+2, 0<x<10

24x+6, x>10

Step-by-step explanation:

Make sure the x>6 has the line under the >. It would not let me enter it like that.

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Z ⊂ Q ⊂ Q ' <br> true or false
gavmur [86]
The answer is so false
3 0
2 years ago
The cylinder shown has a volume of 150 cubic inches and its height is equal to its
harina [27]

Answer:

Volume of sphere = 200 in³

Step-by-step explanation:

Given:

Volume of cylinder = 150 in³

Height = Radius

Radius of cylinder = Radius of sphere

Find:

Volume of sphere = ?

Computation:

Volume\ of\ cylinder = \pi r^2h\\\\Given\ r=h\\\\So, \\\\Volume\ of\ cylinder = \pi r^2r\\\\150 = \pi r^3\\\\

Volume\ of\ sphere =\frac{4}{3} \pi r^3\\\\We\ know \ that , \pi r^3 = 150\\\\ Volume\ of\ sphere =\frac{4}{3} \times 150\\\\Volume\ of\ sphere =200

Volume of sphere = 200 in³

7 0
3 years ago
In the graph below, line k with equation y = -k makes a 45° angle with the x- and y- axes.
tamaranim1 [39]

Answer:

D. (-5,2)

Step-by-step explanation:

1st reflection = reflection across the line k with the rule:

(x,y)→(-y,-x)

So,

(2,5)→(-5,-2)

2nd reflection = reflection across the x-axis with the rule

(x,y)→(x,-y)

So,

(-5,-2)→(-5,2)

After two consecutive reflections

(2,5)→(5,2)

5 0
3 years ago
Read 2 more answers
The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%
vagabundo [1.1K]

Answer:

1) \chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313

2) p_v =P(\chi^2_{3}>16.313)=0.000978

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}

Where O rpresent the observed values and E the expected values.  

State the null and alternative hypothesis

Null hypothesis: The distribution  is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution  is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

E = \% Grand total

E_{Catfish}=500*0.3=150

E_{Bass}=500*0.15=75

E_{Bluegill}=500*0.4=200

E_{Pike}=500*0.15=75

Part 1: Calculate the statistic

\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313

\chi^2 =16.313

Calculate the critical value

First we need to calculate the degrees of freedom given by:

df= (categories-1)=(4-1)= 3

Since the confidence provided is 95% the significance would be \alpha=1-0.95=0.05 and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be \chi^2_{crit}=7.815

We can calculate also the p value:

p_v =P(\chi^2_{3}>16.313)=0.000978

And we got the same decision reject the null hypothesis at 5% of significance.

5 0
3 years ago
Simplify the expression using PEMDAS<br> "15+3-2(2-1) <br> Show me the steps not just the answer!
Vsevolod [243]
Well you have to 1
1. Multiply 2*2-1
2. Add answers 
3. Add 15 
4. There is ur answer which is 15
3 0
3 years ago
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