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2 years ago

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A 35.0 g bullet strikes a 5.3 kg stationary wooden block and embeds itself in the block. The block and bullet fly off together a

t 7.1 m/s. What was the original speed of the bullet? (WILL GIVE BRAINLIEST)

1 answer:

Alisiya [41]2 years ago

3 0

Answer:

= 1200m/s or 1.2 x $10^{3}$ m/s

Explanation:

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Which is the correct answer?

Nezavi [6.7K]

Answer:

Point A

Explanation:

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The potential energy is numerically equal to the work done.

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Among the given values of x the modulus of -5 is the largest.

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3 years ago

As a person squeezes and applies pressure to the outside of a balloon air particles inside

MAVERICK [17]

They will occupy less volume which will cause an increased density of the particles.

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3 years ago

A ball rolls for 8 seconds and travels 24 meters. How fast was it traveling?

belka [17]

Answer:

The speed of the ball was, v = 3 m/s

Explanation:

Given data,

The time period of the ball, t = 8 s

The distance the ball rolled, d = 24 m

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v = d / t m/s

Substituting the given values in the above equation,

v = 24 / 8

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Hence, the speed of the ball was, v = 3 m/s

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3 years ago

A scientist testing to see how a cat “always” lands on their feet drops a cat upside down out of a third story window at a heigh

makkiz [27]

<u>Answer: </u>

Cat has 2.02 seconds to right itself.

<u>Explanation: </u>

Initial height of cat from ground = 20 meter.

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this the velocity of cat in vertical direction = 0 m/s, acceleration = acceleration due to gravity = 9.8 $m/s^2$ , we need to calculate time when s = 20 meter.

Substituting

$20=0*t+\frac{1}{2} *9.8*t^2\\ \\ t = 2.02 seconds$

So, cat has 2.02 seconds to right itself.

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2 years ago

A bug splats against the windshield of a car traveling at high speeds down a backcountry road. Which statement correctly compare

zvonat [6]

Answer:

C. The bug's change in momentum is equal to the car's change in momentum.

Explanation:

As we know by Newton's 2nd law

$F = \frac{\Delta P}{\Delta t}$

here we have also know that when car hits the bug then force applied by wind shield on the bug is same as the force applied by the bug on the car's wind shield as per Newton's III law

$F_{12} = F_{21}$

so we know that

$\frac{\Delta P_{12}}{\Delta t} = \frac{\Delta P_{21}}{\Delta t}$

so we have

$\Delta P_{12} = \Delta P_{21}$

so correct answer will be

C. The bug's change in momentum is equal to the car's change in momentum.

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3 years ago