Answer:
a) They are in the same point
b) t = 0 s, t = 2.27 s, t = 5.73 s
c) t = 1 s, t = 4.33 s
d) t = 2.67 s
Explanation:
Given equations are:


Constants are:

a) "Just after leaving the starting point" means that t = 0. So, if we look the equations, both
and
depend on t and don't have constant terms.
So both cars A and B are in the same point.
b) Firstly, they are in the same point in x = 0 at t = 0. But for generalized case, we must equalize equations and solve quadratic equation where roots will give us proper t value(s).


s,
s
c) Since the distance isn't changing, the velocities are equal. To find velocities, we need to take the derivatives of both equations with respect to time and equalize them.

s,
s
d) For same acceleration, we we need to take the derivatives of velocity equations with respect to time and equalize them.
s
Answer:
44.1613858478 m/s
Explanation:
t = Time taken
u = Initial velocity = 0
v = Final velocity
s = Displacement = 99.4
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s² = a

If air resistance was absent Dan Koko would strike the airbag at 44.1613858478 m/s
Answer:
Explanation:
F=kx
x=F/k
F=2000 kg
x=100 cm=9*10^-3
effective spring constant=k=F/x
k=2000/9*10^-3=2.2*10^-5
now frequency
f=1/2π√k/m
f=1/2*3.14√2.2*10^-5/310
f=1/6.28√7.097*10^-8
f=1/6.28*2.7*10^-4
f=0.16*2.7*10^-4
f=4.32*10^-5
Answer:
Explanation:
When the two dissimilar bodies rubbed together, they the both of the bodies becomes charged. One of the body gets positive charge and the other body gets negative charge.
the positively charged body loses some electrons and the negatively charged body gains some electrons.
According to the properties of charge when the plastic rod is rubbed with the fur, the plastic rod has a tendency to get the negative charge and the fur has a tendency to get positive charge.
So,
When we rub a plastic rod with a piece of fur, electrons--------------transfer from fur----------------to the -------plastic-----. In the result charging fur with -positive-----------charge and plastic rod with-----negative--------charge.
Answer:
51.94 ft/s²
257.63 ft/s
Explanation:
t = Time taken = 4 s
u = Initial velocity = 34 mi/h
v = Final velocity
s = Displacement = 615 ft
a = Acceleration
Converting velocity to ft/s

Equation of motion

Acceleration is 51.94 ft/s²

Final velocity at this time is 257.63 ft/s