2000J
Explanation:
Given parameters:
Extension = 0.5m
Spring constant = 16000N/m
Unknown:
Energy stored in the bow string = ?
Solution:
The energy stored in a bow string is an elastic potential energy.
It can be calculated using the expression below;
Elastic energy = 
K e²
Where k is the spring constant
e is the extension
Input the parameters;
Elastic energy = K e²
= x 16000 x 0.5²
= 2000J
learn more:
Potential energy brainly.com/question/10770261
#learnwithBrainly
Answer:
12.5J
Explanation:
Given parameters:
Mass of bucket = 1.7kg
Height = 75cm = 0.75m
Unknown;
Work done on the bucket by the person = ?
Solution:
To solve this problem, we use the work done equation;
Work done = force x distance = mgh
m is the mass
g is the acceleration due to gravity
h is the height
Now, insert parameters and solve ;
Work done = 1.7 x 9.8 x 0.75 = 12.5J
law of electromagnetic induction hope this helps
Answer:
The velocity of the man from the frame of reference of a stationary observer is, V₂ = 5 m/s
Explanation:
Given,
Your velocity, V₁ = 2 m/
The velocity of the person, V₂ =?
The velocity of the person relative to you, V₂₁ = 3 m/s
According to the relative velocity of two
V₂₁ = V₂ -V₁
∴ V₂ = V₂₁ + V₁
On substitution
V₂ = 3 + 2
= 5 m/s
Hence, the velocity of the man from the frame of reference of a stationary observe is, V₂ = 5 m/s
