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egoroff_w [7]
3 years ago
7

A man pushes an 250-N crate at constant speed a distance of 30.0 m upward along a rough slope that makes an angle of 60° with th

e horizontal. The work done by the force of gravity is:
Physics
1 answer:
mel-nik [20]3 years ago
8 0

Answer:

6495.19 Joule

Explanation:

F = Weight of the crate = 250 N

d = Distance the cart is pushed = 30 m

θ = Angle of inclination = 60°

The weight of the crate will be resloved into two components

Fdsinθ and Fdcosθ

Work done by the force of gravity is

W = Fdsinθ

⇒W = 250×30×sin60

⇒W = 6495.19 Joule

∴ The work done by the force of gravity is 6495.19 Joule

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Answer:

b) TA = TB = TC

Explanation:

  • When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
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       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\  2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

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