Answer:
<h2>Magnitude of the second charge is
![-4.17*10^{-7}C](https://tex.z-dn.net/?f=-4.17%2A10%5E%7B-7%7DC)
</h2>
Explanation:
According to columbs law;
F = ![kq1q2/r^{2}](https://tex.z-dn.net/?f=kq1q2%2Fr%5E%7B2%7D)
F is the attractive or repulsive force between the charges = 12N
q1 and q2 are the charges
let q1 = - 8.0 x 10^-6 C
q2=?
r is the distance between the charges = 0.050m
k is the coulumbs constant =9*10⁹ kg⋅m³⋅s⁻⁴⋅A⁻²
On substituting the given values
12 = 9*10⁹*( - 8.0 x 10^-6)q2/0.050²
Cross multiplying
![0.03=9*10^{9}* -8.0*10^{-6} q2\\0.03 = -72*10^{3} q2\\q2 = \frac{0.03}{ -72*10^{3}} \\q2 = -4.17*10^{-7}C](https://tex.z-dn.net/?f=0.03%3D9%2A10%5E%7B9%7D%2A%20%20-8.0%2A10%5E%7B-6%7D%20q2%5C%5C0.03%20%3D%20-72%2A10%5E%7B3%7D%20q2%5C%5Cq2%20%3D%20%5Cfrac%7B0.03%7D%7B%20-72%2A10%5E%7B3%7D%7D%20%5C%5Cq2%20%3D%20-4.17%2A10%5E%7B-7%7DC)
His velocity is 3 m/s in the direction in which he is running in. which.
Answer:
In the order largest to smallest
Pc = Pb, Pa
Explanation:
Power = Energy expended/time
Pa = 2/2 = 1Watt
Pb = 10/5 = 2Watt
Pc = 2E-3/1E-3 = 2Watt