Answer:
8437.5
Explanation:
By applying the formula of kinetic energy:
Kinetic energy=1/2 mv^2
We make a graphic of this problem to define the angle.
The angle we can calculate through triangle relation, that is,

With this function we should only calculate the derivate in function of c

That is the rate of change of
.
b) At this point we need only make a substitution of 0 for c in the equation previously found.

Hence we have finally the rate of change when c=0.
Answer:
15193.62 m/s
Explanation:
t = Time taken = 6.5 hours
u = Initial velocity = 0 (Assumed)
m = Mass of rocket = 1380 kg
F = Thrust force = 896 N
v = Final velocity
a = Acceleration of the rocket
Force

Equation of motion

The velocity of the rocket after 6.5 hours of thrust is 15193.62 m/s
The answer is true hope that helped!!