All categories

3 years ago

Daltons theory was identified using

Physics

1 answer:

Margaret [11]3 years ago

7 0

<h2>Answer with Explanation </h2>

Dalton’s theory can be classified by the following hypotheses:

1) All material was formed of particles, unbreakable and strong construction segments.

2) All particles of a given component are indistinguishable in volume and characteristics

3) Compounds are determined by a mixture of two or more distinct kinds of atoms.

4) Chemical responses appeared in the rearrangement of the reacting atoms.

This theory was to explain all matter in terms of atoms and their characteristics, the law of conservation of volume and the law of constant composition.

You might be interested in

an object has a momentum of 250 kg m/s what would be the momentum of an object that has half of the mass and going at the same v

Romashka-Z-Leto [24]

The momentum of the second object is 125 kg m/s

Explanation:

The momentum of an object is given by

$p=mv$

where

m is the mass of the object

v is its velocity

For the object in this problem,

$p = 250 kg m/s$

And its mass is m and its velocity is v.

The second object has a mass of $m' = \frac{m}{2}$ and same velocity v, so its momentum is

$p'=m'v = (\frac{m}{2})v=\frac{1}{2}(mv)=\frac{1}{2}p$

So, the second object has a momentum that is half of the momentum of the first object, therefore it is:

$p'=\frac{1}{2}(250)=125 kg m/s$

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

3 0

3 years ago

A ski lift has a one-way length of 1 km and a vertical rise of 200 m. The chairs are spaced 20 m apart, and each chair can seat

RSB [31]

Answer:

Explanation:

The question states that the chairs are spaced 20 m apart through a length of 1 km, or say, 1000 m.

It also does say that each chair weighs 250 kg, and as such the load is

M = 50 * 250

M = 12500.

Taking into consideration, the initial and final heights, we have

h1 = 0, h2 = 200 m

The work needed to raise the chairs,

W = mgh, where h = h2 - h1

W = 12500 * 9.81 * (200 - 0)

W = 2.54*10^7 J

The work is done at a rate of 10 km/h, and at a distance of 1 km, time taken would be

t = 1/10 = 0.1 h or say, 360 s

The power needed thus, is

P = W/t

P = 2.54*10^7 / 360

P = 68125 W, or 68 kW

Initial velocity, u = 0 m/s

Final velocity, v = 10 km/h = 2.78 m/s

Startup time, t is 17 s

Acceleration during the startup then is

a = (v - u)/t

a = 2.78/17

a = 0.163 m/s²

The power needed for the acceleration is

P = ½m [(v² - u²)/t]

P = ½ * 12500 * [2.78²/17]

P = 6250 * 0.455

P = 2844 W

3 0

3 years ago

An observation which is descriptive is considered quantitative, creative, qualitive

Vesnalui [34]

A descriptive observation may very well be a mixture of both quantitative and qualitative as it can utilize elements of both types. Qualitative deals with the kinds of observations that cannot be measured in numerical form. Quantitative data is just that.

3 0

3 years ago

Read 2 more answers

Two hockey players skating on essentially frictionless ice collide head-on. Madeleine, of mass 65.0 kg, is moving at 6.00 m/s to

xeze [42]

Explanation:

It is given that,

Mass of Madeleine, $m_1=65\ kg$

Initial speed of Madeleine, $u_1=6\ m/s$ (due east)

Final speed of Madeleine, $v_1=-3\ m/s$ (due west)

Mass of Buffy, $m_2=55\ kg$

Final speed of Buffy, $v_2=3.5\ m/s$ (due east)

Let $u_1$ is the Buffy's velocity just before the collision. Using the conservation of linear momentum as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$65\times 6+55\times u_2=65\times (-3)+55\times 3.5$

$u_2=-7.13\ m/s$

So, the initial speed of the Buffy just before the collision is 7.13 m/s and it is moving due west. Hence, this is the required solution.

5 0

3 years ago

A researcher is analyzing data from a high-energy particle collision. the result of the analysis gives a value of 8.8 x 10-19 c

Harrizon [31]

Elementary charge used to determine charges of other objects is equal to a charge of electron or proton. It's value is roughly $1.6* 10^{-19} C$ . All other charges are whole-number multipliers of this elementary charge, meaning that we multiply elementary charge by {...,-2,-1,0,1,2,...}.

To find out if the measured charge can be accepted we need to divide it with elementary charge to see if we get whole number as result.
There are three possible values of measured charge: $8.7* 10^{-19} C\\ 8.8* 10^{-19} C \\ 8.9* 10^{-19} C$

$N_{1} = \frac{8.7* 10^{-19} C }{1.6* 10^{-19} C } =5.44 \\ N_{2} = \frac{8.8* 10^{-19} C }{1.6* 10^{-19} C } =5.5 \\ N_{3} = \frac{8.9* 10^{-19} C }{1.6* 10^{-19} C } =5.56$

As we can see none of the possible values of a measured charge is whole-number multiplier of elementary charge so the researcher should not accept the value.
This charge can be achieved by using quarks which have value of 1/3 of elementary charge but they do not remain stable for long enough.

5 0

3 years ago