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beks73 [17]
3 years ago
13

What is the power when a crane lifts a piece of pipe from the ground to a certain height, doing 15000 J of work in 25s?

Physics
1 answer:
egoroff_w [7]3 years ago
5 0

Answer: Option B) 600 W

Explanation:

Since power is the rate of work done per unit time

i.e Power = work/time

Given that:

power of a crane = ?

work done by crane = 15000 J

Time = 25 seconds

Power = 15000J / 25s

Power = 600 watts

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So I'm struggling with rearranging kinematic formulas. Does anyone have any steps or something to help.
bekas [8.4K]

Rearranging formulas is all about simple algebra rules. Just like when solving for x in an equation, you're just isolating whichever variable you want. I'll work this one out for you and hopefully it'll help, but if you need more explanation, then feel free to comment!

D = ViT + 0.5at²   Subtract ViT from both sides

D - ViT = 0.5at²    Divide both sides by 0.5t²

\frac{D - ViT}{0.5t^{2} } = \frac{0.5at^{2} }{0.5t^{2} }    I wrote this step out a little more to show how your fraction will cancel

\frac{D - ViT}{0.5t^{2} }= a    I like to flip these around so the single variable is on the right

a = \frac{D - ViT}{0.5t^{2} }

7 0
3 years ago
27 degrees to kelvin, 20 dg to milligrams, and 3 to decimeters.
Gala2k [10]
K = C + 273, so 27°C = 27+273 = 300 K

1 dg = 100 mg, so 20 dg = 20×100 = 2,000 mg
7 0
3 years ago
What are particles of carbon called?
Ainat [17]
Co2 or greenhouse gas
8 0
3 years ago
Explain why objects moving in fluids must have special shapes ?
Alexus [3.1K]

Explanation:

Fluids exert both drag and lift forces on moving objects.  Drag is the frictional force opposing motion.  Lift is the force perpendicular to motion.

Some objects, like parachutes, are designed with large cross sectional areas to increase drag force.  Usually though, objects are designed to minimize drag force.  It's why cars, planes, and boats have sleek shapes.

Airplane wings have shapes called airfoils that generate lift.  It's what makes them fly.  The same shape is found in racecar spoilers.  These spoilers use lift force to push down on the rear tires, increasing traction.

8 0
3 years ago
A steel ball bearing with a radius of 1.5 cm forms an image of an object that has been placed 1.1 cm away from the bearing’s sur
Nonamiya [84]

Answer:

Check the explanation

Explanation:

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

The image is virtual

The image is upright

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

Kindly check the diagram in the attached image below.

5 0
3 years ago
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