There is no adjustment in gravity, yet there is an adjustment in 'weightness'.
Gravitational compel and weight with respect to an edge are not similar things, despite the fact that it is normally educated something else.
Weight is really the aggregate of gravitational powers and of inertial drive for a question very still (no Coriolis compel) in a given casing.
In the event that the Earth were not pivoting, weight would increment most at the Equator and be unaltered at the Poles.
Nuclear energy has practically no harmful emission (unless you consider water vapour to be bad).
The correct answer is option C. i.e. 4%
<span>The total thickness of the stack of sheets is measured to be (0.80 ± 0.02) mm.
The maximum true thickness will be </span>(0.80 + 0.02) mm. = 1.00 mm
Ans, the maximum uncertainity will be <span> (0.20 + 0.02) mm = +/-0.04 mm
Thus, the four sheets true thickness will be </span>1.00 mm +/-0.04 mm
Thus, single sheet thickness will be 0.250 mm +/-0.01 mm
Thus, percentage error = (0.01/0.25) * 100 = 4%
<span>3640 m/s
The de Broglie wavelength of a particle is expressed by the equation:
λ = h/p
where
λ = wavelength
h = Planck constant
p = momentum
so let's solve for momentum and the substitute the known values and calculate:
λ = h/p
λp = h
p = h/λ
p = 6.62607004x10^-34 Js/2x10^-7 m
p = 6.62607004x10^-34 kg*m^2/s^2 * s/2x10^-7 m
p =3.31303502x10^-27 kg*m/s
Now momentum is defined as mass times velocity. And the mass of an electron is 9.10938356Ă—10^-31 kg. So
p = mv
p/m = v
3.31303502x10^-27 kg*m/s / 9.10938356Ă—10^-31 kg = v
3.63694754774384x10^3 m/s = v
Rounding to 3 significant figures gives 3.64x10^3 m/s or 3640 m/s. That velocity is low enough that we don't need to worry about relativistic effects.</span>
