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2 years ago

If a wave hits a smooth surface at an angle of incidence of 40 degrees, the angle of reflection is

Physics

2 answers:

ruslelena [56]2 years ago

8 0

A, 40 degrees. Reflexion laws state that both incidence and reflection angles are the same.

bezimeni [28]2 years ago

4 0

40 degrees since its a reflection meaning its the same thing, a mimic. you dont multiply, add, or subtract. simply your answer is in the question

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A 1.5 kg orange falls from a tree and hits the ground in 0.75s. What is the speed of the orange just before it hits the ground?

Olenka [21]

The final speed of the orange is 7.35 m/s

Explanation:

The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration $g=9.8 m/s^2$ towards the ground. So we can use the following suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time elapsed

For the orange in this problem, we have

u = 0 (it is dropped from rest)

$a=g=9.8 m/s^2$ is the acceleration

Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:

$v=0+(9.8)(0.75)=7.35 m/s$

Learn more about free fall:

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8 0

2 years ago

A 4.60 gg coin is placed 19.0 cmcm from the center of a turntable. The coin has static and kinetic coefficients of friction with

Komok [63]

Answer:

62.64 RPM.

Explanation:

Given that

m= 4.6 g

r= 19 cm

μs = 0.820

μk = 0.440.

The angular speed of the turntable = ω rad/s

Condition just before the slipping starts

The maximum value of the static friction force =Centripetal force

$\mu_s\ m g=m\ \omega^2\ r\\ \omega^2=\dfrac{\mu_s\ m g}{m r}\\ \omega=\sqrt{\dfrac{\mu_s\ g}{ r}}\\ \omega=\sqrt{\dfrac{0.82\times 10}{ 0.19}}\ rad/s\\\omega= 6.56\ rad/s$

$\omega=\dfrac{2\pi N}{60}\\N=\dfrac{60\times \omega}{2\pi }\\N=\dfrac{60\times 6.56}{2\pi }\ RPM\\N=62.64\ RPM$

Therefore the speed in RPM will be 62.64 RPM.

5 0

2 years ago

In terms of saturation (unsaturated, saturated, super-saturated). How would you classify the following?

miskamm [114]

Answer:

1. A NaCl solution with a concentration of 50g/100mL of water at 40°C: The NaCl solution with a given concentration is saturated at this temperature .As the temperature increases the solution will more dissolves.

2. A sugar solution with a concentration of 200g/100mL of water at 40°C: The sugar solution with a given concentration is saturated at this temperature. As the temperature increases the solution will more dissolves.

3. A sugar solution with a concentration of 240g/100mL of water at 40°C: The sugar solution with a given concentration is saturated at given temperature.

7 0

3 years ago

Can someone help with just question 1 :)

Elanso [62]

Can you show the full question?

3 0

2 years ago

Which example nest represents balanced forces ???

n200080 [17]

Answer:

an elevator stopped on the third floor a basketball shot into a hoop a sled sliding down a snowy hill a tow truck pulling a car out of a ditch

5 0

2 years ago