Answer:
Explanation:
Given that,
Bathysphere radius
r = 1.5m
Mass of bathysphere
M = 1.2 × 10⁴ kg
Constant speed of descending.
v = 1.2m/s
Resistive force
Fr = 1100N upward direction
Density of water
ρ = 1.03 × 10³kg/m³
The volume of the bathysphere can be calculated using
V = 4πr³ / 3
V = 4π × 1.5³ / 3
V = 14.14 m³
The Bouyant force can be calculated using
Fb = ρgV
Fb = 1.03 × 10³ × 9.81 × 14.14
Fb = 142,846.18 N
Buoyant force is acting upward
Weight of the bathysphere
W = mg
W = 1.2 × 10⁴ × 9.81
W = 117,720 N
Weight is acting downward
The net positive buoyant using resolving
Fb+ = Fb — W
Fb+ = 142,846.18 — 117,720
Fb+ = 25,126.18 N
The force acting downward is the weight of the submarine and it is equal to the positive buoyant force and the resistive force
W = Fb+ + Fr
W = 25,126.18 + 1100
W = 26,226.18
mg = 26,226.18
m = 26,226.18 / 9.81
m = 2673.4kg
Mass of submarine is 2673.4kg
Answer:
356 000 J
Explanation:
Total Energy released
= Energy released when water cools to 0 + Energy released when water is converted to ice at 0
= mcT + ml
= (0.5)(4200)(90-0) + (0.5)(334 000)
= 189 000 J + 167 000 J
= <u>3</u><u>5</u><u>6</u><u> </u><u>0</u><u>0</u><u>0</u><u> </u><u>J</u>
Answer:
0.1667Hz
Explanation:
by explanation frequency is given by 1/time
after carrying out the calculation of time we can easily get frequency.
time=speed/distance
=18/3
=6s
but frequency=1/time
hence=1/6
=0.1667hertz
Acceleration = (change in speed) / (time for the change)
Change in speed = (ending speed) - (starting speed)
Change in speed = (60 km/hr) - (50 km/hr) = 10 km/hr
Time for the change = 12 sec
Acceleration = (10 km/hr) / (12 sec)
Acceleration = 0.8333 km/hr-sec
Convert to a unit that we can understand:
Acceleration = (0.8333 km/hr-sec)x(1000 m/km)x(hr/3600sec)
Acceleration = (833.3 / 3600) (m-hr / hr-sec²)
Acceleration = (833.3 / 3600) (m/s²)
<em>Acceleration = 0.231 m/s² </em> or 0.833 km/hr-sec²
Answer:
<h3>The answer is 90 m/s</h3>
Explanation:
To find the final velocity of an object given it's initial velocity , time taken and it's acceleration we use the formula
<h3>v = u + at </h3>
where
v is the final velocity
u is the initial velocity
t is the time taken
a is the acceleration
From the question
u = 40 m/s
t = 10s
a = 5 m/s²
We have
v = 40 + 5(10) = 40 + 50
We have the final answer as
<h3>90 m/s</h3>
Hope this helps you
