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baherus [9]
3 years ago
6

A motorcyclist changes the velocity of his bike from 20.0 meters/second to 35.0 meters/second under a constant acceleration of 4

.00 meters/second2. How long does it take the bike to reach the final velocity?
Physics
1 answer:
Fiesta28 [93]3 years ago
4 0
35-20 = 15m/s difference
15/4 = 3.75 seconds
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<em>The range is 15.15 m and the time in the air is 1.01 s</em>

Explanation:

<u>Horizontal Motion</u>

When an object is thrown horizontally (with angle 0°) with a speed v from a height h, it follows a curved path ruled exclusively by gravity until it eventually hits the ground.

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To calculate the time the object takes to hit the ground, we use the equation below:

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\displaystyle d=15\cdot\sqrt{\frac  {2*5}{9.8}}=15*1.01

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The time in the air is:

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t = 1.01 s

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