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baherus [9]
3 years ago
6

A motorcyclist changes the velocity of his bike from 20.0 meters/second to 35.0 meters/second under a constant acceleration of 4

.00 meters/second2. How long does it take the bike to reach the final velocity?
Physics
1 answer:
Fiesta28 [93]3 years ago
4 0
35-20 = 15m/s difference
15/4 = 3.75 seconds
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If you lift the front wheel of a poorly maintained bicycle off the ground and then start it spinning at 0.69 rev/s , friction in
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Answer:

magnitude of the frictional torque is 0.11 Nm

Explanation:

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Final angular velocity w = 0 (since it stops)

Time t = 13 secs

Using w = w° + §t

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O = 4.34 + 13§

§ = -4.34/13 = -0.33 rad/s2

The negative sign implies it's a negative acceleration.

Frictional torque that brought it to rest must be equal to the original torque.

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