A motorcyclist changes the velocity of his bike from 20.0 meters/second to 35.0 meters/second under a constant acceleration of 4
1 answer:
You might be interested in
Answer:
The radiation pressure of the light is 3.33 x 10⁻⁶ Pa.
Explanation:
Given;
intensity of light, I = 1 kW/m²
The radiation pressure of light is given as;
I kW = 1000 J/s
The energy flux density = 1000 J/m².s
The speed of light = 3 x 10⁸ m/s
Thus, the radiation pressure of the light is calculated as;
Therefore, the radiation pressure of the light is 3.33 x 10⁻⁶ Pa.
Answer:
It is real, inverted, and smaller than the object.
Explanation:
Let's start by using the lens equation to find the location of the image:
where we have:
q = ? is the distance of the image from the lens
f = 15 cm is the focal length (positive for a converging lens)
p = 50 cm is the distance of the object from the lens
Solving the equation for q, we find
The sign of q is positive, so the image is real.
Now let's also write the magnification equation:
where
are the size of the image and of the object
By substituting p = 50 cm and q = 21.3 cm, we find
So we notice that:
: this means that the image is smaller than the object
: this means that the image is inverted
so, the correct option is:
It is real, inverted, and smaller than the object.
Answer:
(a) a = 2.44 m/s²
(b) s = 63.24 m
Explanation:
(a)
We will use the second equation of motion here:
where,
s = distance covered = 47 m
vi = initial speed = 0 m/s
t = time taken = 6.2 s
a = acceleration = ?
Therefore,
<u>a = 2.44 m/s²</u>
<u></u>
(b)
Now, we will again use the second equation of motion for the complete length of the inclined plane:
where,
s = distance covered = ?
vi = initial speed = 0 m/s
t = time taken = 7.2 s
a = acceleration = 2.44 m/s²
Therefore,
<u>s = 63.24 m</u>