1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goblinko [34]
3 years ago
6

What is the weight of an object with a force of 35 pounds ?

Physics
1 answer:
Reika [66]3 years ago
8 0

Answer:

Wouldn't it be 17.5. Force doubles in weight.

Explanation:

You might be interested in
You shine a LASER from the air into water. What happens to light?
GarryVolchara [31]
The answer is B! Hope this helps
5 0
3 years ago
What happens if you reverse the galaxy motion and go back in time?
bulgar [2K]
It’s called mirror universe
7 0
3 years ago
Scientists use this part of the electromagnetic spectrum to diagnose broken bones. X–rays infrared waves gamma rays ultraviolet
Snezhnost [94]

X-rays are used to identify broken bones


4 0
3 years ago
Read 2 more answers
hello, I need help with a 25 question test! Which statement is an example of heat transfer by convection?Question 4 options:Jane
garri49 [273]
\begin{gathered} Heat\text{ transfer by }convection\text{ }occurs\text{ on fluids like air or water, hence, an example of heat } \\ \text{transfer by convection is: "Hot air from the sand rose and was replace by cool aire blowing} \\ in\text{ from the ocean as a sea bre}eze." \end{gathered}

3 0
1 year ago
How much kinetic energy does a system containing 3 moles of an ideal gas at 300 K possess? What is the heat capacity at constant
ElenaW [278]

Answer:

1. K.E = 11.2239 kJ ≈ 11.224 kJ

2. C_{V} = 37.413 JK^{- 1}

3. Q = 10.7749 kJ

Solution:

Now, the kinetic energy of an ideal gas per mole is given by:

K.E = \frac{3}{2}mRT

where

m = no. of moles = 3

R = Rydberg's constant = 8.314 J/mol.K

Temperature, T = 300 K

Therefore,

K.E = \frac{3}{2}\times 3\times 8.314\times 300

K.E = 11223.9 J = 11.2239 kJ ≈ 11.224 kJ

Now,

The heat capacity at constant volume is:

C_{V} = \frac{3}{2}mR

C_{V} = \frac{3}{2}\times 3\times 8.314 = 37.413 JK^{- 1}

Now,

Required heat transfer to raise the temperature by 15^{\circ} is:

Q = C_{V}\Delta T

\Delta T = 15^{\circ} = 273 + 15 = 288 K

Q = 37.413\times 288 = 10774.9 J = 10.7749 kJ

8 0
3 years ago
Other questions:
  • A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The uppe
    5·1 answer
  • The frequency of a microwave is 1.2 x 10^9 hertz. what is the wavelength of the given problem.
    7·1 answer
  • What holds the stars together in their galaxies? A. light B. orbits of the planets C. weight D. gravity
    9·2 answers
  • Show the equation of simple pendulum to be dimensionally consistent
    7·1 answer
  • A student who takes a multiple-choice test by reading the stem of each item, generating the correct response before looking at t
    15·1 answer
  • Does friction always oppose relative motion?
    14·1 answer
  • Why was basketball invented?
    7·1 answer
  • A basketball with a mass of 0.5 kilograms is accelerated at 2
    12·1 answer
  • What is the speed of a horse in meters per second that runs a distance of 1.2 miles in 2.4 minutes​
    11·1 answer
  • Describe how the boiling point of water on top of a mountain would be different from its boiling point at sea level.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!