Gravitational Potential Energy = weight x height
for 1 meter:
GPE = 5 x 1
= <u>5N</u>
for 1.5 metres:
GPE = 5 x 1.5
= <u>7.5N</u>
for 2 metres:
GPE = 5 x 2
= <u>10N</u>
Answer:
1. A substance that can be separated into two or more substances only by a chemical change is a(n) _____.
solution
element
mixture
compound
2.
Which of the following materials is a substance?
air
gasoline
stainless steel
silver
3.
The first figure in a properly written chemical symbol always is _____.
boldfaced
capitalized
italicized
underlined
4.
Which of the following represents a compound?
H
H-3
H2O
O-16
5. What do chemical symbols and formulas represent, respectively?
elements and compounds
atoms and mixtures
compounds and mixtures
elements and ions
Explanation:
Answer:
10
Explanation:
Given that :
Initial Velocity (u) = 25 m/s
Range can be obtained using the relation :
Range = (u² * sin2θ) / g
g = 10m/s ; θ = 45
Range = [10² * sin2(45)] / 10
Range = [100 * 1] ÷ 10
Range = 10
The Modified Mercalli scale is used measures the amount of damage done during an earthquake. This helps to locate the epicenter of the earthquake. It depicts the intensity of the earthquake based on the damage occurred due to the earthquake. The responses from many people who experienced the earthquake are collected by the scientists, assigned a value and plotted on a map
The plotted number can change with the reference place within the region of disturbance. It depends on the location of the observer with reference to the epicenter of the earthquake. The reporting depends on the witness. Some can exaggerate the extent of damage caused. All the above mentioned are possible sources of error when using the Modified Mercalli scale to locate the earthquake's epicenter.
Answer:
Explanation:
Your numbers seem wonky, so I'll just assume that the initial displacement is a distance A (Amplitude) from the equilibrium position. Spring constant = k
Initial potential energy is
PE = ½kA²
As potential energy and kinetic energy are constantly exchanging in SHM,
the position x where half of the original spring potential exists is found where
½kx² = ½(½kA²)
x² = ½A²
x = (√0.5)A
x ≈ 0.707A
just plug in your actual starting position A
With A = 5.2 cm
x = 3.67695... 3.7 cm
