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3 years ago

Need help!! will give brainliest! 7th grade math

Mathematics

2 answers:

Andru [333]3 years ago

8 0

Answer:To check if a given value is a solution to an equation:

Evaluate the left-hand side expression at the given value to get a number.

Evaluate the right-hand side expression at the given value to get a number.

See if the numbers match.

Yeah he is right it is 17 for the first one

Step-by-step explanation:

const2013 [10]3 years ago

6 0

Answer:

The first question is 17.

Step-by-step explanation:

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Had 6 bagels and ate all but 4 of them. how many bagels were left?

Basile [38]

You will have 2 bagels left

3 0

3 years ago

Christian gave keven 6 blueberries. Keven gave San 6 blueberries how much dose Keven have left

il63 [147K]

Answer:

So if Keven started with 0 he then got 6 then gave it away, that means he simply had none to himself.

4 0

3 years ago

Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217

Soloha48 [4]

Answer:

$f(216) \approx 6.0093$

Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

Linear approximated as:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

$f(x) = \sqrt[3]{216}$

$f(x) = 6$

So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

$f(215 + 1) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

$f(x) = x^\frac{1}{3}$

Differentiate

$f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}$

Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

$f'(216) = \frac{6}{648}$

$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

$f(216) \approx 6 + 0.0093$

$f(216) \approx 6.0093$

6 0

3 years ago

X+y+2=-5 -2x-y+2=-1 x-2y-2=0 solve algebraically

Rina8888 [55]

Answer:

x+y+2=-5 -2x-y+2=-1 x-2y-2=0 solve algebraically

x+y+2=-5 equation 1

-2x-y+2=-1 equation 2

x-2y-2=0 equation 3

Add equation 1 + 2+ 3

x+y+2=-5 + -2x-y+2+1 + x-2y-2

x+y+2= -7+2+1-2x+x+y

x+y+2= -4-x+y

x+y+2+4+x-y= 0

2x+6= 0

2x= -6

divide both side by 2

x= -3

from equation 1 insert x

x+y+2=-5

since x=-3

then, -3+2+y= -5

-1+y= -5

y= -5+1

y= -4

Step-by-step explanation:

7 0

3 years ago

Please help pleaseeee I really need answers only

stiks02 [169]

☁️ Answer ☁️

5. IS E (none of these)

Because I got:

-125y^5/162x

6. X = 5/3

Hope it helps.

Have a nice day noona/hyung.

7 0

2 years ago

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