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Triss [41]
3 years ago
7

what happens to the current in a circuit if the resitance of the components in the circuit is increased​

Physics
1 answer:
Anit [1.1K]3 years ago
7 0

Answer:

The current decreases.

Explanation:

Current and resistance are inversely proportional. The equation connecting current, resistance and voltage is V = IR, where V is voltage, I is current and R is resistance.

Rearranging this equation, you get:

I = \frac{V}{R}

and

R = \frac{V}{I}

If the value of voltage in both equations remains constant, and the value of R decreases, the value of I will increase. Conversely, if in the second equation R = \frac{V}{I} , the value of V remains constant the value of I decreases, then the value of R, resistance will increase.

Thus, it can be seen that the current will decrease as resistance increases and vice versa.

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tankabanditka [31]

Answer:

All the answers are solved and explained below.

Explanation:

Note: This questions lacks the initial and most necessary data to answer these following questions. I have found a related question. I will be considering that question to carry out the answers.

Question: A car with a mass of 1000 kg is at rest at a spotlight. when the light turns green, it is pushed by a net force of 2000 N for 10 s. (This was the information missing in this question).

Data Given:

m = 1000 kg

F = 2000N

t = 10s

Q1 Solution:

Acceleration = a = ?

F = ma

a = F/m

a = 2000/ 1000

a = 2 m/s^{2}

Q2: Solution:

Change in velocity = Δv = ?

acceleration = change in velocity / time

a = Δv/t

Δv = axt

Δv = 2 x 10

Δv = 20 m/s

Q3: Solution:

Impulse = I = ?

Impulse = Force x time

I = 2000 x 10

I = 20000 Ns

Q4: Solution:

Change in Momentum = Δp = ?

Δp = mΔv

Δp = 1000 x 20

Δp = 20000 Kgm/s

Q5: Solution:

Final velocity of the car at the end of 10 seconds = vf = ?

Δp = m x Δv

Δp = m x (vf-vi)

Δp = 1000 x (vf - 0 )

20000 = 1000 x vf

vf = 20000/1000

vf = 20 m/s

Q6: Solution:

Change in momentum the car experiences as it continues at this velocity?

Δp = ?

Δp = mΔv

Δp = m x (0)

Δp = 0

Q7: Solution:

Impulse = Change in momentum

Impulse = Δp

Implulse = 0

Q8: Solution:

Change in momentum = Δp = mΔv

Δp = m(vf-vi)

Δp = 1000 x (0-20)

Δp = -20000 kgm/s

Q9: Solution:

Impulse = Δp

Impulse = -20000 Ns

Q10: Solution:

Impulse = ?

Impulse = F x t

F = impulse/t

F = -20000/4s

F = -5000 N

Q11: Solution:

F = ma

a = ?

a = F/m

a = -5000/1000

a = -5m/s^{2}

6 0
3 years ago
You lift a 45-newton bag of mulch 1.2 meters and carry it a distance of 10 meters to the garden. How much 
zysi [14]
To lift the bag straight up takes (F · D) = (45 · 1.2) = 54 joules of energy (work).

Moving the bag horizontally 'across' gravity requires no work.
It doesn't matter how far.
4 0
4 years ago
A 2200 kg car starts from rest and speeds up to 12 m/s in 5.2 s. The net force acting on the car is?
zmey [24]
The acceleration is 12(m/s)/5.2s = 2.308m/s^2
F=ma, so
F=2200*2.308 = 5076.9N
6 0
3 years ago
Why can't passenger planes fly very high?
nalin [4]
The higher in the atmosphere, the less oxygen, and the more cold temperatures.

The material/moisture on the plane would freeze and damage the engine.
8 0
3 years ago
Read 2 more answers
An archer aims his arrow directly at an orange hanging on an orange tree. At the moment he releases the arrow, the orange drops
Elena L [17]

Answer:

Yes it would

Explanation:

As the arrow and the orange are in the same position initially, vertically speaking. They are also subjected to the same gravitational acceleration g only in the vertical direction. They also start their motion at the same time. So their equation of motion can be written as

y = h + gt^2/2

Where h is the initial height of both of them. Since their g, h, and t are the same, their vertical position must be the same at the same time. As the arrows progress horizontally, it would hit the orange.

6 0
3 years ago
Read 2 more answers
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