Ask question

Ask question

All categories

3 years ago

13

An airplane pilot sets a compass course due west and maintains an airspeed of 210 km/h. After flying for a time of 0.490 h, she

finds herself over a town a distance 121 km west and a distance 20 km south of her starting point.Find the magnitude of the wind velocity.

2 answers:

tankabanditka [31]3 years ago

5 0

Answer:

$V_{A/E}=55.23km/h\\or\\V_{A/E}=15.342m/s$

Explanation:

The velocity of plane relative to earth is given by:

$V_{P/E}=\frac{d}{t}\\V_{P/E}=\frac{[-121i-20j]km}{0.490h} \\V_{P/E}=[-247i-41j]km/h$

As the from given data.The velocity of plane relative to air is:

$V_{P/A}=[-210i]km/h$

According to relative motion of velocity of the air relative to earth given by:

$V_{A/E}=V_{P/E}-V_{P/A} \\V_{A/E}=[(-247i-41j)km/h]-(-210i)km/h\\V_{A/E}=[-37i-41j]km/h\\$

The magnitude is given as:

$V_{A/E}=\sqrt{(37)^{2}+(41)^{2} }\\ V_{A/E}=55.23km/h\\or\\V_{A/E}=15.342m/s$

Andrei [34K]3 years ago

5 0

Answer:

55km/h , 47.87° south west or 227.87°

Explanation:

If there is no wind then the plane would be at a distance

d=(210 km/h)(0.49h) = 102.9 km west of the starting point.

if the wind is blown then then the plane is 121 km - 102.9 km = 18.1 km west and 20 km south in the time 0.49 h.

Velocity of the plane in west direction=(18.1 km) / 0.49 h = 36.9 km/h

velocity of the plane in south direction=(20 km) / 0.49 h = 40.8 km/h

Now the wind velocity is

$\sqrt{(36.9^2 + 40.8^2}$

= 55.01 km/h

The direction is

θ =tan⁻¹ (40.8 / 36.9)

θ = 47.87° south west or 227.87°

You might be interested in

How does a helicopter fly ? ( I need it explained in the view of physics)

Zielflug [23.3K]

Answer:

because blades of helicopter create a high pressure difference between lower and higher portion of blade so due to this pressure difference helicopter became able to fly.

Explanation:

for instant answer

join wats up group

just scan it

post question

get answer from trusted experts for free

3 0

3 years ago

Read 2 more answers

A 50g ball is released from rest 1.0 above the bottom of thetrack

ludmilkaskok [199]

Answer:

The maximum height of the ball is 2 m.

Explanation:

Given that,

Mass of ball = 50 g

Height = 1.0 m

Angle = 30°

The equation is

$y=\dfrac{1}{4}x^2$

We need to calculate the velocity

Using conservation of energy

$\Delta U_{i}+\Delta K_{i}=\Delta K_{f}+\Delta U_{f}$

Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

$\Delta U_{i}=\Delta K_{f}$

Put the value into the formula

$mgh=\dfrac{1}{2}mv^2$

Put the value into the formula

$50\times10^{-3}\times9.8\times1.0=\dfrac{1}{2}\times50\times10^{-3}\times v^2$

$v^2=\dfrac{2\times50\times10^{-3}\times9.8\times1.0}{50\times10^{-3}}$

$v=\sqrt{19.6}$

$v=4.42\ m/s$

We need to calculate the maximum height of the ball

Using again conservation of energy

$\dfrac{1}{2}mv^2=mgh$

Here, h = y highest point

Put the value into the formula

$\dfrac{1}{2}\times50\times10^{-3}\times(4.42)^2=50\times10^{-3}\times9.8\times h$

$y=\dfrac{0.5\times(4.42)^2}{9.8}$

$y=0.996\ m$

Put the value of y in the given equation

$y=\dfrac{1}{4}x^2$

$x^2=4\times0.996$

$x=\sqrt{4\times0.996}$

$x=1.99\ m\ \approx 2 m$

Hence, The maximum height of the ball is 2 m.

4 0

3 years ago

A pebble is thrown into a calm lake, ripples are formed from the center and move outward. The water particles in the lake travel

Misha Larkins [42]

Answer: The option (C) is correct. The energy travels horizontally.

Explanation: When the pebble is thrown into a calm lake, there will be disturbance in the lake. The ripples are formed from the center and move outward because the energy is carried out from particle to particle.

The distribution of the energy among the particles starts from center and it will carry out outward. This disturbance will occur horizontally.

Therefore, the energy travels horizontally.

7 0

3 years ago

PLEASE HURTY FAT ON QUIZ ATM!!!! 25 POINTS!!!!!! A student pushes a 40-N walk across the floor for a distance of 10 m how much w

algol13

Work is force times distance, so W = 40 N * 10 m = 400 J

8 0

3 years ago

Â (a) How long can you rapidly climb stairs (116/min) on the 166.0 kcal of energy in a 200g apple? (b) How many flights is this

adoni [48]

Answer:

a) It will take you 16.94 min to climb the stairs.

b) The numbers of flights are 123 flights.

Explanation:

a) Let the energy consumption while climbing the stairs be 685 W in kcal/min is given by:

rate of energy consumption = (685 W)×[(0.01433kcal/min)/1 W]

= 9.81605 kcal/min

the time it takes to climb the stairs is given by:

t = E/P

= (166.0 kcal)/(9.8 kcal/min)

= 16.94 min

Therefore, it will take you 16.94 min to climb the stairs.

b) Given t is the time it takes to climb stairs and N is the number of stairs to climb per min, then the number of stairs is:

n = t×N

= (16.94)×(116)

= 1965 stairs

given the number of stairs each flight as N1, then the number of flights is given by:

flights = n/N1

= (1965)/(16)

= 123 flights

Therefore, the numbers of flights are 123 flights.

7 0

3 years ago