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Anton [14]
3 years ago
6

When 6 g of granulated Zn is added to a solution of 2 M HCl in a beaker at room temperature, hydrogen gas is generated. How woul

d the rate be affected if, at constant volume of the acid, 6 g of powdered Zn is used. The rate of hydrogen gas evolution will be ______.
Chemistry
1 answer:
timama [110]3 years ago
4 0

Answer: increased

Explanation:

Powdered zinc has a greater surface area than zinc granules. If the same mass of zinc and volume of acid is used, it will be observed that the powdered zinc will react faster since it provides a greater surface area for reaction compared to zinc granules. The greater the available surface area of reactants, the greater the rate of reaction. Higher surface area means that more particles are available for reaction.

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What is the capillary rise of ethanol in a glass tube with a 0.1 mm radius if the surface tension of ethanol is 0.032Jm2 and the
iragen [17]

Answer:

Explanation:

Expression for capillary rise is as follows

h = 2T / ρ g r where T is surface tension , ρ is density of liquid and r is radius of capillary tube.

T = .032 J m⁻²

ρ = .71 g / cm³

= 7100 kg / m³

r = .1 x 10⁻³ m = 10⁻⁴ m

h = 2 x .032 / (7100 x 9.8 x 10⁻⁴ )

h = .0092 m

= 9.2 mm .

5 0
2 years ago
A gas cylinder of volume 5.00 l contains 1.00 g of ar and 0.500 g of ne. the temperature is 275 k. find the partial pressure of
amid [387]
<span>11.3 kPa The ideal gas law is PV = nRT where P = Pressure V = Volume n = number of moles R = Ideal gas constant (8.3144598 L*kPa/(K*mol) ) T = Absolute temperature We have everything except moles and volume. But we can calculate moles by starting with the atomic weight of argon and neon. Atomic weight argon = 39.948 Atomic weight neon = 20.1797 Moles Ar = 1.00 g / 39.948 g/mol = 0.025032542 mol Moles Ne = 0.500 g / 20.1797 g/mol = 0.024777375 mol Total moles gas particles = 0.025032542 mol + 0.024777375 mol = 0.049809918 mol Now take the ideal gas equation and solve for P, then substitute known values and solve. PV = nRT P = nRT/V P = 0.049809918 mol * 8.3144598 L*kPa/(K*mol) * 275 K/5.00 L P = 113.8892033 L*kPa / 5.00 L P = 22.77784066 kPa Now let's determine the percent of pressure provided by neon by calculating the percentage of neon atoms. Divide the number of moles of neon by the total number of moles. 0.024777375 mol / 0.049809918 mol = 0.497438592 Now multiply by the pressure 0.497438592 * 22.77784066 kPa = 11.33057699 kPa Round the result to 3 significant figures, giving 11.3 kPa</span>
8 0
2 years ago
Find the area given rectangle.
seraphim [82]

Answer:

The perimeter of a Rectangle P= 2(l + b)

Area of a Rectangle A = l × b

3 0
3 years ago
Why is the chemistry of actinoids complicated?
gladu [14]

Answer:

Explanation:

Actinoids are the series have 15 element in the periodic table.

Chemistry of actinoids are complicated because of the following reasons.

  • Their outer most orbitals are 6d and 7s but most of the electrons resides in 5f orbitals. These orbitals are most exposed to environment and incoming electron picked up by 5f orbital instead of 6d or 7s orbitals.
  • They are radioactive elements that couldn't be handle in normal condition to study their properties.
  • Their f-orbital can accommodate 14 electrons and they have many variable oxidation state.
  • 5d electron donot contribute in the formation of chemical bonds.
  • They have a very strong tendency to make complexes
  • Most of the actinoides are artificial and are in very minute in amount. they are in very less quantity that is amounts found in nano-grams so are more expensive too and
  • As they are radioactive so their half life is very short and in very less time the decay occur so couldn't be study as upon decay their actual properties changed.

Due to all the above reasons it make difficult for a chemist to study about the chemical properties of actinoids.

8 0
3 years ago
A student constructs a galvanic cell that has a strip of iron metal immersed in a solution of 0.1M Fe(NO3)2 as one half-cell and
MrMuchimi

Answer:

Fe

Explanation:

The cell potential is:

ΔE°cell = E°red(red) - E°red(oxid)

Where, E°red(red) is the reduction potential of the substance that is reducing, and E°red(oxid) is the reduction potential of the substance that is oxidizing. For the reaction be spontaneous and happen, ΔE°cell > 0.

The reduction takes place in the cathode, which is the negative pole, and the oxidation in the anode, which is the positive pole. So, the electrons flow from the positive pole to the negative pole (anode to cathode).

Then, if the voltmeter measured a negative potential, it means that is was attached incorrectly. So, the anode is Fe.

4 0
2 years ago
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