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Brut [27]
3 years ago
6

Help Tell me the answer.

Chemistry
1 answer:
Paladinen [302]3 years ago
5 0

Answer:

it's easy u just have to put them in a calculator the way they are it will give you your answer atleast I think so hope this helps

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You know that breaking up the tablet increases the surface area of the seltzer. So what could you conclude about the relationshi
oksano4ka [1.4K]

Answer:

Grinding or breaking an Alka-Seltzer tablet increases the number of particles and increases the surface area. Material which was within the tablet is exposed, allowing for more collisions between reactant particles and resulting in an increased rate of reaction.

4 0
2 years ago
What is the ph of a peach with a [ –oh] = 3.2 × 10 –11 m?
iogann1982 [59]
H+= 10^-14 / [OH-1 = 3.125 * 10^-4 M
pH=-log(H+) = 3.505

Just round it down and your answer = 3.5
3 0
2 years ago
Question 1 Multiple Choice Worth 2 points)<br> (03.05 LC)<br> Which statement is true?
Tasya [4]

Answer:

I need more information. What is the question?

7 0
3 years ago
A 2.912 g sample of a compounds containing only C, H, and O was completely oxidized in a reaction that yielded 3.123 g of water
Taya2010 [7]

Answer:

Explanation:

18 gram of water contains 2 g of hydrogen

3.123 gram of water will contain 2 x 3.123 / 18 = .347 g of hydrogen .

44 gram of carbon dioxide contains 12 g of carbon

7.691 gram of carbon dioxide will contain 12 x 7.691 / 44 = 2.1 g of carbon .

So the sample will contain 2.912 - ( .347 + 2.1 ) g of oxygen .

= .465 g of oxygen .

moles of Carbon = 2.1 / 12 = .175

moles of hydrogen = .347 / 1 = .347

moles of oxygen = .465 / 16 = .029

Ratio of moles of carbon , oxygen and hydrogen ( C,O,H )

= 0.175 : 0.029 : 0.347

= .175/ .029 : 1 : .347 / .029

= 6 : 1 : 12

So empirical formula = C₆H₁₂O

Let the molecular formula be (C_6H_{12}O)_n

molecular weight = n ( 6 x 12 + 12x 1 + 16)

= 100 n

Given 100 n = 100.1

n = 1

Molecular formula = C₆H₁₂O.

3 0
3 years ago
What is the structure of an artery ?
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Well this is a bio question but it goes the tunica interna the tunica media then the tunica externa.
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