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matrenka [14]
3 years ago
11

How do I do this question

Mathematics
1 answer:
aliya0001 [1]3 years ago
7 0

Answer:

Step-by-step explanation:

Join OB.

∠A=∠A  (common)

\frac{AP}{AO} =\frac{\frac{1}{2} AO}{AO} =\frac{1}{2} \\\frac{AQ}{AB} =\frac{\frac{1}{2} AB}{AB} =\frac{1}{2} \\\frac{AP}{AO} =\frac{AQ}{AB}

∴ ΔAPO and ΔAOB are similar.

\frac{PQ}{OB} =\frac{1}{2} \\

∠P=∠O

∠Q=∠B

So PQ║OB

Similarly RS║OB

∴PQ║RS

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What are the zeros of the polynomial function f(x)=x^3-5x^2-6x ?
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Option C

The zeros of the polynomial function f(x) = x^3 - 5x^2 - 6x is x = 0 and x = -1 and x = 6

<h3><u>Solution:</u></h3>

Given that polynomial function is f(x) = x^3 - 5x^2 - 6x

We have to find the zeros of polynomial

To find zeros, equate the given polynomial function to 0. i.e f(x) = 0

x^3 - 5x^2 - 6x = 0

Taking "x" as common term,

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Equating each term to zero, we get

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We can rewrite -5x as -6x + x

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Taking "x" as common from first two terms and -6 as common from next two terms

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Taking (x + 1) as common term,

(x + 1)(x - 6) = 0

x + 1 = 0 and x - 6 = 0

x = -1 and x = 6

Thus the zeros of given function is x = 0 and x = -1 and x = 6

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