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olga55 [171]
3 years ago
12

2.

Physics
1 answer:
larisa [96]3 years ago
3 0

Answer:

Aceleración, a = 2 m/s²

Explanation:

Dados los siguientes datos;

Velocidad inicial = 108 km/h

Tiempo = 10 segundos

Velocidad final = 36 km/h

To find the average acceleration;

Conversión:

36 km/h to meters per seconds = 36*1000/3600 = 10 m/s

108 km/h to meters per seconds = 108*1000/3600 = 30 m/s

I. Para encontrar la aceleración, usaríamos la primera ecuación de movimiento;

V = U + at

Dónde;

V es la velocidad final.

U es la velocidad inicial.

a es la aceleración.

t es el tiempo medido en segundos.

Sustituyendo en la fórmula, tenemos;

30 = 10 + a*10

30 = 10 + 10a

10a = 30 - 10

10a = 20

Aceleracion = \frac{20}{10}

Aceleración, a = 2 m/s²

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Answer:

wdym

Explanation:

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3 years ago
Which portion of the electromagnetic spectrum can the human eye detect? *
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Answer:

B. Only wavelengths between infrared and ultraviolet

Explanation:

That is the visible spectrum if you look up a diagram of the light spectrum.

6 0
3 years ago
The electric field everywhere on the surface of a thin, spherical shell of radius 0.750 m is of magnitude 890 N/C and points rad
andrezito [222]

Answer:

55.6 nC

Explanation:

The electric field at the surface of a charged sphere has the same expression of the electric field produced by a single point charge located at the centre of the sphere and having the same charge of the sphere, so it is given by

E=k\frac{Q}{r^2}

where

k=9\cdot 10^9 N m^2 C^{-2} is the Coulomb's constant

Q is the charge on the sphere

r is the radius of the sphere

In this problem we know

E = 890 N/C is the magnitude of the electric field on the sphere

r = 0.750 m is the radius of the sphere

So by re-arranging the equation we can find the net charge on the sphere:

Q=\frac{Er^2}{k}=\frac{(890)(0.750)^2}{9\cdot 10^9}=5.56\cdot 10^{-8} C=55.6 nC

5 0
4 years ago
Por un solenoide de 6500 espiras y 25 cm de longitud circula una corriente de 0,6 amperios. ¿Cuál es el valor del campo magnétic
9966 [12]

Answer:

Magnetic field, B = 0.0196 T

Explanation:

A current of 0.6 amps flows through a solenoid 6500 turns and 25 cm long. What is the value of the magnetic field inside it?

We have,

Current, I = 0.6 A

Number of turns in the solenoid, N = 6500

Length of solenoid, l = 25 cm = 0.25 m

The magnetic field inside the solenoid is given by :

B=\mu_o\dfrac{N}{l}I\\\\B=\dfrac{4\pi \times 10^{-7}\times 6500\times 0.6}{0.25}\\\\B=0.0196\ T

So, the value of the magnetic field inside the solenoid is 0.0196 T.

8 0
4 years ago
The swinging pendulum has 10 joules of potential energy at its maximum height at points (1) and (5). If the mass of the pendulum
SVEN [57.7K]

The speed of the pendulum at point 3 is 1.4 m/s

Explanation:

We can solve this problem by using the law of conservation of energy. In fact, the mechanical energy of the pendulum (which is the sum of his potential energy + his kinetic energy) must be conserved. So we can write:

U_1 +K_1 = U_3 + K_3

where

U_1 is the initial potential energy, at the highest position

K_1 is the initial kinetic energy, at the highest position

U_3 is the final potential energy, at the lowest position

K_3 is the final kinetic energy, at the lowest position

We are told that:

U_1 = 10 J is the potential energy of the pendulum at the maximum height

K_1 = 0 (when the pendulum is at maximum height, the speed is zero, so the kinetic energy is zero)

U_3 = 0 (potential energy is zero at the lowest position)

Therefore,

K_3 = U_1 = 10 J

Kinetic energy can be rewritten as

K_3 = \frac{1}{2}mv^2

where

m = 10 kg is the mass of the pendulum

v is its speed at point 3

Solving for v,

v=\sqrt{\frac{2K_3}{m}}=\sqrt{\frac{2(10)}{10}}=1.4 m/s

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

4 0
3 years ago
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