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Vinvika [58]
2 years ago
8

Next, Stacy measures two quantities: the mass of each washer and the force that the washers exert on the force meter. In general

, how will the force change as she adds more washers to the meter?
Physics
1 answer:
leva [86]2 years ago
6 0

The force that the washers exert on the force meter will increase as she adds more washers to the meter.

<h3>What is the relationship between force and mass?</h3>

Force exerted by a body is directly proportional to the mass of the body.

Force increases with increase in mass.

The increase in the mass of the washers will result in an increase in the force exerted by the washers.

Therefore, the force that the washers exert on the force meter will increase as she adds more washers to the meter.

Learn more about force and mass at: brainly.com/question/15368078

#SPJ1

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I think hes cool

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An imaginary line perpendicular to a reflecting surface is called ____refrac_____.
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Water can dissolve almost anything in the universe
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Answer:

No, its not possible for water to dissolve almost anything in the universe.

Explanation:

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5 0
3 years ago
Based on what you learn about jovian moons by watching the videos or reading your textbook, what types of evidence for recent or
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Answer:

b. craters, river valleys feeding into surface lakes of very cold liquids

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7 0
3 years ago
A copper rod of cross-sectional area 11.6 cm2 has one end immersed in boiling water and the other in an ice-water mixture, which
julia-pushkina [17]

Answer:

0.686 g of ice melts each second.

Solution:

As per the question:

Cross-sectional Area of the Copper Rod, A = 11.6\ cm^{2} = 11.6\times 10^{- 4}\ m^{2}

Length of the rod, L = 19.6 cm = 0.196 m

Thermal conductivity of Copper, K = 390\ W/m.^{\circ}C

Conduction of heat from the rod per second is given by:

q = \frac{KA\Delta T}{L}

where

\Delta T = 100^{\circ} - 0^{\circ} = 100^{\circ}C = temperature difference between the two ends of the rod.

Thus

q = \frac{390\times 11.6\times 10^{- 4}\times 100}{0.196} = 228.48\ J/s

Now,

To calculate the mass, M of the ice melted per sec:

M = \frac{q}{L_{w}}

where

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5 0
3 years ago
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