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Vinvika [58]
2 years ago
8

Next, Stacy measures two quantities: the mass of each washer and the force that the washers exert on the force meter. In general

, how will the force change as she adds more washers to the meter?
Physics
1 answer:
leva [86]2 years ago
6 0

The force that the washers exert on the force meter will increase as she adds more washers to the meter.

<h3>What is the relationship between force and mass?</h3>

Force exerted by a body is directly proportional to the mass of the body.

Force increases with increase in mass.

The increase in the mass of the washers will result in an increase in the force exerted by the washers.

Therefore, the force that the washers exert on the force meter will increase as she adds more washers to the meter.

Learn more about force and mass at: brainly.com/question/15368078

#SPJ1

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In which condition the acceleration of a moving vehicle become zero​
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Explanation:

When,the vehicle has uniform velocity, it's acceleration becomes zero

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An aquifer pump test was conducted in a confined aquifer where the initial piezometric surface was at elevation 12.45 m, and wel
murzikaleks [220]

Answer:

T = 0.0088 m²/s

Explanation:

given,

initial piezometric elevation = 12.5 m

thickness of aquifer = 14 m

discharge = 28.24 L/s = 0.02824 m³/s

we know                              

k = \dfrac{qln(\dfrac{R_2}{R_1})}{2\pi D(H_2-H_1)}

k = \dfrac{0.02824 \times ln(\dfrac{75}{25})}{2\pi \times 14 (11.45-10.89)}                                                                        

k = 0.629 mm/sec

Transmissibilty

T = k × H                          

T = 0.629 × 14 × 10⁻³

T = 0.0088 m²/s

4 0
3 years ago
Which type of force pulls objects toward one another
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Gravity ALWAYS does that, and electrostatic force does it when two objects have opposite charges.
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The equivalence between gravitational and inertial mass is explained in : the set of all of the events that happened on Earth
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The correct answer is theory of general relativity.

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According to Einestine both the forces are indistinguishable  as both the forces produce same effects. Thus both are equivalent and thus gravity is a phenomenon that can be analysed in a radically different way which gives some strange results such as bending of light, existence of black holes,e.t.c

6 0
3 years ago
Write an email to a classmate explaining why the velocity of the current in a river has no FN C02-F20-OP11USB effect on the time
anzhelika [568]

The velocity of the current in a river has no effect on the the time it takes to paddle a canoe across the river, given that the boat is pointed perpendicular to the bank of the river, because

The velocity of the river does not change the velocity and therefore the distance traveled in the direction of the boat which is directed perpendicular to it

Reason:

Let \overset \rightarrow {v_y} represent the velocity of the boat across the river in the direction, \overset \rightarrow {d_y}, and let, \overset \rightarrow {v_x}, represent the velocity of the river, we have;

The velocity of the boat perpendicular to the direction of the river = \overset \rightarrow {v_y}

Therefore, the distance covered per unit time in the perpendicular direction

to the flow of the river is \overset \rightarrow {v_y}, such that the time it takes to cross the river in

the perpendicular direction is the same, for every value of the velocity of

the river.

This is so because the velocity in the perpendicular direction to the flow of

the river, which is the velocity of the boat is unchanged by the velocity of

the river, because there is no perpendicular component of velocity in the

velocity of the river.

\overset \rightarrow {v_y} = 3 m/s

\overset \rightarrow {v_x} = 4 m/s

The width of the river, w_y = 6 meters, we have;

  • The resultant velocity = \sqrt{(3 \ m/s)^2 + (4 \ m/s)^2} =5 \ m/s

The direction, θ, is given as follows;

\theta = \arctan \left(\dfrac{4}{3} \right) \approx 53.13^{\circ}

The length of the path of the boat, <em>l</em>, is given as follows;

l = \dfrac{6}{cos \left(\arctan \left(\dfrac{4}{3} \right)\right)} = 10

The length of the path the boat takes = 10 m

The time it takes to cross the river, t = \dfrac{l}{v}, therefore;

  • t = \dfrac{10}{5} = 2
  • The time it takes to cross the river, t = 2 seconds

Considering only the y-components, we have;

t = \dfrac{w_y}{v_y}

Therefore;

t = \dfrac{6 \ m}{3 \ m/s} = 2 \, s

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vectors of the velocities of the river and the boat are perpendicular, the

distance covered in the direction of the boat is unaffected by the velocity

of the river.

Learn more vectors here:

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