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Vinvika [58]
1 year ago
8

Next, Stacy measures two quantities: the mass of each washer and the force that the washers exert on the force meter. In general

, how will the force change as she adds more washers to the meter?
Physics
1 answer:
leva [86]1 year ago
6 0

The force that the washers exert on the force meter will increase as she adds more washers to the meter.

<h3>What is the relationship between force and mass?</h3>

Force exerted by a body is directly proportional to the mass of the body.

Force increases with increase in mass.

The increase in the mass of the washers will result in an increase in the force exerted by the washers.

Therefore, the force that the washers exert on the force meter will increase as she adds more washers to the meter.

Learn more about force and mass at: brainly.com/question/15368078

#SPJ1

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I wish to use a step up transformer to turn an initial RMS AC voltage of 100 V into a final RMS AC voltage of 200 V. What is the
zhuklara [117]

Answer:

1:2

Explanation:

It is given that,

Initial RMS AC voltage is 100 V and final RMS AC voltage is 200 V.

We need to find the ratio of the number of turns in the primary to the secondary  for step up transformer.

For a transformer, \dfrac{V_1}{V_2}=\dfrac{N_1}{N_2}

So,

\dfrac{N_1}{N_2}=\dfrac{100}{200}\\\\\dfrac{N_1}{N_2}=\dfrac{1}{2}

So, the ratio of the number of turns in the primary to the secondary is 1:2.

4 0
3 years ago
An important diagnostic tool for heart disease is the pressure difference between blood pressure in the heart and in the aorta l
butalik [34]

Answer:

a)   f ’’ = f₀ \frac{1 + \frac{v}{c} }{1- \frac{v}{c} } , b)   Δf = 2 f₀ \frac{v}{c}

Explanation:

a) This is a Doppler effect exercise, which we must solve in two parts in the first the emitter is fixed and in the second when the sound is reflected the emitter is mobile.

Let's look for the frequency (f ’) that the mobile aorta receives, the blood is leaving the aorta or is moving towards the source

                    f ’= fo\frac{c+v}{c}

This sound wave is reflected by the blood that becomes the emitter, mobile and the receiver is fixed.

                   f ’’ = f’ \frac{c}{ c-v}

where c represents the sound velocity in stationary blood

therefore the received frequency is

                 f ’’ = f₀   \frac{c}{c-v}

let's simplify the expression

                f ’’ = f₀ \frac{c+v}{c-v}

                f ’’ = f₀ \frac{1 + \frac{v}{c} }{1- \frac{v}{c} }

         

b) At the low speed limit v <c, we can expand the quantity

                 (1 -x)ⁿ = 1 - x + n (n-1) x² + ...

                 ( 1- \frac{v}{c} ) ^{-1} = 1 + \frac{v}{c}

 

                f ’’ = fo ( 1+ \frac{v}{c}) ( 1 + \frac{v}{c} )

                f ’’ = fo ( 1 + 2 \frac{v}{c} + \frac{v^2}{ c^2} )

leave the linear term

               f ’’ = f₀ + f₀ 2\frac{v}{c}

the sound difference

               f ’’ -f₀ = 2f₀ v/c

               Δf = 2 f₀ \frac{v}{c}

4 0
2 years ago
An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid
Setler79 [48]

Answer:

a)

- 7.04\times10^{11} J

b)

5.03\times10^{5} N

Explanation:

a)

m = mass of the asteroid = 43000 kg

v_{o} = initial speed of asteroid = 7600 m/s

v = final speed of asteroid = 5000 m/s

W = Work done by the force on asteroid

Using work-change in kinetic energy theorem

W = (0.5) m (v^{2} - v_{o}^{2})\\W = (0.5) (43000) (5000^{2} - 7600^{2})\\W = - 7.04\times10^{11} J

b)

F = magnitude of force on asteroid

d = distance traveled by asteroid while it slows down = 1.4 x 10⁶ m

Work done by the force on the asteroid to slow it down is given as

W = - F d\\- 7.04\times10^{11} = - F (1.4\times10^{6})\\F = 5.03\times10^{5} N

4 0
3 years ago
In order for an object to accelerate, a forcegravityfrictiona swing must be applied.
vodomira [7]
<span>In order for an object to accelerate, a <u>force</u> must be applied. It follows Newton’s second law of motion where it states that a body at rest remains at rest unless a force is acted upon it. When you move an object, you are exerting a force onto it. By exerting a force on the object, you are actually displacing it from its initial position. You cannot apply force to the object without altering its position. Keep in mind that when you exert work, you are exerting energy too. </span>
4 0
3 years ago
On the sunlit surface of Venus, the atmospheric pressure is 9.0 106 Pa, and the temperature is 740 K. On the earth's surface the
iren2701 [21]

Answer:

the ratio (N/V)Venus / (N/V)Earth = 39 : 1

Explanation:

Detailed explanation and calculation is shown in the image below

3 0
3 years ago
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