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Nezavi [6.7K]
3 years ago
15

How much speed is needed for an object to travel 250 km in 1.5 hrs? * Your answer

Physics
1 answer:
NemiM [27]3 years ago
7 0

Answer: 166.67km/hr

Explanation:

Given the following :

Distance traveled = 250km

Time taken = 1.5 hours

Recall :

Speed = Distance traveled / time taken

Speed = 250 km / 1.5 hours

Speed = 166. 67 km/hr

Speed in m/s:

166.67km/hr = (166.67 × 1000)m / 3600 s

= 166670m / 3600s

= 46.3m/s

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Two soccer players kick a soccer ball back and forth along a straight line. The first player kicks the ball 16 m to the right to
Oliga [24]

Answer:

a

The total distance is d_t =19.1 m

b

The displacement is

  D_t = 12.9m

Explanation:

From the question we are told that

        Distance traveled by the ball for first player d_f = 16m to the right

        Distance  traveled by the ball for second player d_s = 3.1 m to the left

       

The total distance traveled by the ball is mathematically represented as

                   d_t = d_f + d_s

Substituting values

                  d_t = 16 + 3.1

                  d_t =19.1 m

The displacement is mathematically represented as

              D_t  = d_f -d_s

This is because displacement deal with direction and from the question we are told that right is positive and left is negative

          Substituting values  

                D_t = 16 -3.1

                 D_t = 12.9m

     

5 0
3 years ago
(11%) Problem 5: A uniform stationary ladder of length L = 2.7 m and mass M = 11 kg leans against a smooth vertical wall, while
jeka94

Answer:

970.2 N

Explanation:

We are given that

Length of ladder=2.7 m

Mass,M=11 kg

Coefficient of friction=\mu=0.45

\theta=51^{\circ}

Mass of painter=8M

Distance from base=d

We have to find the magnitude of the normal force exerted by the floor on the ladder.

Normal force exerted by floor on the ladder=mg+8mg=9mg

Where g=9.8m/s^2

Normal force exerted by floor on the ladder=9\times 11\times 9.8=970.2N

7 0
3 years ago
• what is the typical distance between two adjacent pins on a 14-pin dual-in-line ic package?
muminat

A 14 pin dual-in-line IC package[14 DIL] is an integrated socket which is most popular form of IC package and has a wide range of application in digital electronics.

The 14-pin DIL has two pairs per side and each pair contains seven connecting pins.

The pairs of pins are arranged linearly one after another.The typical dimensions of width is 6.5 mm and the typical dimension of length is 18 mm.

we are asked to calculate the typical distance between two adjacent pins.

The typical distance between two adjacent pins is calculated as-

                                                                 Typical\ distance =\frac{dimensional\ length}{number\ of\ pins\ in\ each\ row}

                                    =\frac{18 mm}{7}

                                    = 2.5714 mm    [ans]                  

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We need to learn about median and mode because they are both important in statistical data and statistical data is what shows us important information about the world around us.
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