Answer:
Element
Explanation:
This is a pure substance which can't be split into simpler substances by chemical means
C = 12.818 mg CO2 (1 mmol CO2/44 mg CO2) (1 mmol C/1 mmol
CO2) = 0.29 mmol
H = 3.675 mg of H2O (1 mmol H2O/18 mg H2O) (2 mmol H/1
mmol H2O) = 0.41 mmol
N = (4.725 mg – 0.29 * 12 – 0.41 * 1) * (1 mmol/14 mg) =
0.06 mmol
Divide everything by the smallest number:
C = 0.29/0.06 = 4.8 ~ 5
<span>H = 0.41/0.06 = 6.8 ~
7</span>
N = 0.06/0.06 = 1
Empirical formula is:
<span>C5H7N</span>
Answer:
The most notable of these are known as the "six simple machines": the wheel and axle, the lever, the inclined plane, the pulley, the screw, and the wedge, although the latter three are actually just extensions or combinations of the first three.
Answer:
Mass = 8 g
Explanation:
Given data:
Mass of MgO formed = 20 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of MgO:
Number of moles = mass/molar mass
Number of moles = 20 g/ 40 g/mol
Number of moles = 0.5 mol
Now we will compare the moles of MgO and O₂ from balance chemical equation:
MgO : O₂
2 : 1
0.5 : 1/2×0.5 = 0.25 mol
Mass of oxygen required:
Mass = number of moles × molar mass
Molar mass of O₂ is 32 g/mol
Mass = 0.25 mol × 32 g/mol
Mass = 8 g
