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77julia77 [94]
3 years ago
9

A line that passes through the origin also passes through the point (6,2). What is the slope of the line?

Mathematics
1 answer:
Yanka [14]3 years ago
5 0

9514 1404 393

Answer:

  1/3

Step-by-step explanation:

The slope of a line is the ratio of its "rise" to its "run." The "rise" is the change in vertical distance, and the "run" is the corresponding change in horizontal distance between two points on the line. The formula for the slope is ...

  m=\dfrac{y_2-y_1}{x_2-x_1}\qquad\text{where $(x_1,y_1)$ and $(x_2,y_2)$ are points on the line}

In this problem, you are told the line passes through the origin, which is point (x, y) = (0, 0), and through point (6, 2). Using these coordinates in the slope formula gives ...

  m=\dfrac{2-0}{6-0}=\dfrac{2}{6}=\boxed{\dfrac{1}{3}}

__

You may notice that when the line passes through the origin, the slope is simply the ratio y/x of any point on the line. Here, that ratio is 2/6 = 1/3.

_____

<em>Additional comment</em>

A line through the origin is the graph of a <em>proportional</em> relationship. That is, y is proportional to x. The slope of the line is the <em>constant of proportionality</em>. The equation of the line is ...

  y = kx . . . . . . where k is the constant of proportionality.

The line in this problem statement will have the equation ...

  y = (1/3)x

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Answer:

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⇒70°+∠8=180°  [∠4=70°]

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But if these two angles i.e ∠4 and ∠8 forms a linear pair.Then

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<u>4th possibility</u>

If If ∠4 and ∠8 are corresponding angles.

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