Answer:
The other angle is 75⁰
Explanation:
Given;
velocity of the projectile, v = 10 m/s
range of the projectile, R = 5.1 m
angle of projection, 15⁰
The range of a projectile is given as;
To find another angle of projection to give the same range;
<u>Check: </u>
sin(2θ) = sin(2 x 75) = sin(150) = 0.5
sin(2θ) = sin(2 x 15) = sin(30) = 0.5
A 20.-N force stretches the spring by 1.00 m - 0.50 m = 0.50 m, so by Hooke's law the spring constant is k such that
20. N = k (0.50 m)
⇒ k = (20. N) / (0.50 m) = 40 N/m
Position and momentum.
This is Heisenberg's Uncertainty Principle:
Δx Δp ≥ h ÷ 4π, where Δx is the change in position, Δp is the change in momentum, and h is Planck's Constant.
There's actually only one latitude implied by anything attached the question . . . Zero, since there are no choices listed.
That's brilliant ! Because zero latitude (the equator) IS the place on Earth where tangential speed is greatest.
Very clever !
