How many joules of heat would be required to heat 0.5 kg of aluminum by 2 kelvin

A brick with a mass of 20 kg and a weight of 196 N is released on a frictionless plane at an angle of 30°. What is the accelerat

Veronika [31]

Answer:4.9m/s^2

Basically answer A

Explanation:

6 0

4 years ago

The curve below shows the percentage of population of aquatic species that die in response to doses of pollutant A:

Elis [28]

Based on the trend produced by the dose - response graph, it would be best to evacuate the residents in other to prevent the increasing percentage of deaths due to the rising level of pollutant A.

The curve shows that the pollutant level in mg/kg of pollutant A is still increasing, hence, groundwater monitoring alone won't be the best decision to make.

Since the pollutant level is still increasing, then the spill level still need effective monitoring.

Evacuation of residents seems to be the best decision that should be taken based on the information interpreted on the graph.

Therefore, Evacuating residents to prevent rising death percentage is required as the pollutant level is yet to subside.

Learn more :brainly.com/question/24844489

8 0

3 years ago

Is visible light a form of<br> radiation? Explain.

natali 33 [55]

Answer:

Yes,in fact visible 'light' is a form of radiation, which can be defined as an energy that travels in the form of electromagnetic waves. It can also be described as a flow of particle-like 'wave-packets', called photons, that travel constantly at the speed of light (about 300 000 kilometres per second).

Explanation:

6 0

3 years ago

An equilibrium constant is not changed by a change in pressure <br> a. True<br> b. False

Umnica [9.8K]

Hi There! :)

An equilibrium constant is not changed by a change in pressurea. True
b. False

False! :P

7 0

3 years ago

Read 2 more answers

A small airplane takes on 302 l of fuel. If the density of the fuel is 0.821 g/ml, what mass of fuel has the airplane taken on?

ella [17]

To calculate the mass of the fuel, we use the formula

$m = V \times \rho$

Here, m is the mass of fuel, V is the volume of the fuel and its value is $V =302 \ L = 302 \ L \times \frac{10^{3}m L }{L} = 302 \times 10^{3} \ mL$ and $\rho$ is the density and its value of 0.821 g/mL.

Substituting these values in above relation, we get

$m = 302 \times 10^{3} \ mL \times 0.821 g/mL = 247942 g \\\\ m = 247. 94 \ kg$

Thus, the mass of the fuel 247 .94 kg.

8 0

3 years ago