Use of the empirical formula
D) Sulphur i think thats correct
The reaction formula is 2HCl + Mg = MgCl2 + H2. There are one atom of magnesium involved and the number of atoms will not change, So the answer is one magnesium ion.
When it switches to a lower orbital, the atom emits energy in the form of photons.
Answer:
D) 1 iron(II), 2 chloride
Explanation:
Iron II chloride is the compound; FeCl2. It is formed as follows, ionically;
Fe^2+(aq) + 2Cl^-(aq) -----> FeCl2
The formation of one mole of FeCl2 involves the reaction one mole of iron and two moles of chloride ions. This means that in FeCl2, the ratio of iron to chlorine is 1:2 as seen above.
Therefore there is one iron II ion and two chloride ions in each mole of iron II chloride, hence the answer.
