Answer:
a = 0.016 m/s^2
the airplane's acceleration is 0.016 m/s^2
Explanation:
Applying the equation of motion;
v^2 = u^2 + 2as ........1
Where;
v = final velocity = 47.5 m/s
u = initial velocity = 28.9 m/s
a = acceleration
s = displacement = 45300m
From equation 1, making a the subject of formula;
v^2 = u^2 + 2as
2as = v^2 - u^2
a = (v^2 - u^2)/2s
Substituting the given values;
a = (47.5^2 - 28.9^2)/(2×45300)
a = 0.015684768211 m/s^2
a = 0.016 m/s^2
the airplane's acceleration is 0.016 m/s^2
Apparent diameter is the answer
Answer:
The maximum potential energy of the net, compared to its unstretched potential energy, is: 
Explanation:
From the question we are told that
The weight of the man is 
The distance of the window to the net is 
The distance stretched by net is 
Generally from the of conservation energy , the total energy is conserved
This implies that
Where 
is the initial potential energy of the , man which is mathematically evaluated as
Substituting values
And 
is the unstretched potential energy of the net
And 
is the final potential energy of the man which is mathematically evaluated as
Substituting values
The negative show that the direction of the man is against the direction of gravitational pull
And 
is the maximum potential energy of the net when stretched
So the above equation becomes
So
I think you cant subtract this because you have no like terms. So the answer is the question.
Answer:
ΔU=0.8834 Btu
Explanation:
Given data
Area of piston A=40 in²
The weight W=100 lbf
Atmospheric Pressure P=14.7 lbf/in²
Work added E=3 Btu
The change in elevation Δh=1 ft =12 inch
To find
Change in internal energy of the gas ΔU
Solution
For Piston
ΔPE=| W+(P×A)×Δh |
ΔPE=| 100+(14.7×40)×12 |
ΔPE=8256 lbf.in
ΔPE=8256×0.000107
ΔPE=0.8834 Btu
From law of conservation of energy then ,the charging in the potential energy of the piston is made by exerting force by gas
Wgas= -ΔPE
Wgas= -0.8834 Btu
For the gas as a system and by applying first law of thermodynamics
Q-W=ΔU
0-(-0.8834 Btu)=ΔU
So
ΔU=0.8834 Btu
