Answer:
45.8 mL
Explanation:
If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.
P₁ = 3.1 atm P₂ = 10.5 atm
V₁ = 155 mL V₂ = ? mL
P₁V₁ = P₂V₂ <----- Boyle's Law equation
(3.1 atm)(155 mL) = (10.5 atm)V₂ <----- Insert values
480.5 = (10.5 atm)V₂ <----- Multiply 3.1 and 155
45.8 = V₂ <----- Divide both sides by 10.5
There are 145 centimeters in 1.45 meters.
Answer:
- the electromagnetic spectrum is the range of electromagnetic radiation, organized by how much energy the radiation carries. there is an opposite relationship between wavelength, frequency, and energy. as the wavelength of a wave increases, the frequency and energy decrease, and vice versa.
- the order from longest wavelength (lowest energy) to shortest wavelength (highest energy) is as follows: radio waves, microwaves, infrared waves, visible light waves, ultraviolet waves, x-rays and gamma rays.
Explanation:
hope this helps!
The chemical reaction equation for this is
XeF6 + 3H2 ---> Xe + 6HF
Assuming gas behaves ideally, we use the ideal gas formula to solve for number of moles H2 with T = 318.15K (45C), P = 6.46 atm, V = 0.579L. Then we use the gas constant R = 0.08206 L atm K-1 mol-1.
we get n = 0.1433 moles H2
to get the mass of XeF6,
we divide 0.1433 moles H2 by 3 since 1 mole XeF6 needs 3 moles H2 to react then multiply by the molecular weight of XeF6 which is 245.28 g/mole XeF6.
0.1433 moles H2 x

x

= 11.71 g XeF6
Therefore, 11.71 g of XeF6 is needed to completely react with 0.579 L of Hydrogen gas at 45 degrees Celcius and 6.46 atm.
Answer:
The International Date Line passes through the mid-Pacific Ocean and roughly follows a 180 degrees longitude north-south
line on the Earth. It is located halfway round the world from the prime meridian—the zero degrees longitude established in Greenwich