Answer:
1. 1.33 gram of carbon
2. 2.38g of carbon dioxide
Explanation:
From the given information:
Total amount of CO₂ = 4.86 grams
Atomic mass of C = 12 g/mole
molar mass of CO₂ = 44 g/mole
∴
The mass of the Carbon (C) in grams is:
![= Total\ amount \ of \ CO_2 \times \dfrac{12 \ g/mol}{44 \ g/mol}](https://tex.z-dn.net/?f=%3D%20Total%5C%20amount%20%5C%20of%20%5C%20CO_2%20%5Ctimes%20%5Cdfrac%7B12%20%5C%20g%2Fmol%7D%7B44%20%5C%20g%2Fmol%7D)
![= 4.86 \ g \times \dfrac{12 \ g/mol}{44 \ g/mol}](https://tex.z-dn.net/?f=%3D%204.86%20%5C%20g%20%20%5Ctimes%20%5Cdfrac%7B12%20%5C%20g%2Fmol%7D%7B44%20%5C%20g%2Fmol%7D)
= 1.33 gram of carbon
2.
Here, the total amount of CO₂ = unknown
Atomic mass of O₂ = 32 g/mole
molar mass of CO₂ = 44 g/mole
amount of oxygen = 1.73 g
∴
The mass of CO₂ = ![Total \ amount \ of \ O_2 \times \dfrac{44 \ g/mol}{32\ g/mol}](https://tex.z-dn.net/?f=Total%20%5C%20amount%20%5C%20of%20%5C%20O_2%20%5Ctimes%20%5Cdfrac%7B44%20%5C%20g%2Fmol%7D%7B32%5C%20g%2Fmol%7D)
![=1.73 \times \dfrac{44 \ g/mol}{32\ g/mol}](https://tex.z-dn.net/?f=%3D1.73%20%20%5Ctimes%20%5Cdfrac%7B44%20%5C%20g%2Fmol%7D%7B32%5C%20g%2Fmol%7D)
= 2.38 g of carbon dioxide
Charcoal because of its surface area
Answer:
This is because it is a physical change not a chemical change.
If Thomson's atomic theory was accurate, the positively charged particles would have gone through the foil. The balanced positive charges and negative charges within the atom would have made the atom neutral, and the positive charges would not have been concentrated enough to cause deflection.