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lesya [120]
3 years ago
5

Plz answer as soon as possible!!

Chemistry
1 answer:
lesya [120]3 years ago
8 0

Answer:

Explanation:

shared pair of electrons= covalent bond (sharing of electrons allows atoms to complete octet and gain stability)

unshared pair of electrons= lone pair/ non-bonding pairs

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What is the mass in grams of BaCl2 that is needed to prepare 200 mL of a 0.500 M solution
DENIUS [597]

Answer:

= 20.82 g of BaCl2

Explanation:

Given,

Volume = 200 mL

Molarity = 0.500 M

Therefore;

Moles = molarity × volume

          = 0.2 L × 0.5 M

          = 0.1 mole

But; molar mass of BaCl2 is 208.236 g/mole

Therefore; 0.1 mole of BaCl2 will be equivalent to;

  = 208.236 g/mol x 0.1 mol

  = 20.82 g

Therefore, the mass of BaCl2 in grams required is 20.82 g

6 0
3 years ago
E ) The distribution coefficient , Ko ( Cether / C water ) , for an organic substance X at room temperature is 13. What relative
TiliK225 [7]

Answer:

Relative volume of ether to water that should be used for the extraction = 1.205

Explanation:

The extraction/distribution coefficient of an arbitrary solvent to water for a given substance is expressed as the mass concentration of the substance in the arbitrary solvent (C₁) divided by the mass concentration of the substance in water (C₂).

K = (C₁/C₂)

Let the initial mass of the organic substance X in water be 1 g (it could be any mass basically, it is just to select a right basis, since we are basically working with percentages here).

If 94% of the organic substance X is extracted by ether in a single extraction, 0.94 g ends up in ether and 0.06 g of the organic substance X that remains in water.

Let the volume of ether required be x mL.

Let the volume of water required be y mL.

Relative volume of ether to water that should be used for the extraction = (x/y)

Mass concentration of the organic substance X in ether = (0.94/x)

Mass concentration of organic substance X in water = (0.06/y)

The distribution coefficient , Ko (Cether / C water), for an organic substance X at room temperature is 13.

13 = (0.94/x) ÷ (0.06/y)

13 = (0.94/x) × (y/0.06)

13 = (15.667y/x)

(x/y) = (15.667/13) = 1.205

Hope this Helps!!!

4 0
3 years ago
The following chemical equation is unbalanced. When the equation is balanced, what is the coefficient for pure calcium (Ca)? A.
erik [133]
<span>3Ca + 2AlPO4 -> 2Al + Ca3(PO4)2 . . .the coefficient for Ca is 3.</span>
5 0
3 years ago
Read 2 more answers
The pH of saliva is normally in the range of 6.4 to 7.0. However, when a person is ill, the person's saliva becomes more acidic.
aleksley [76]

Answer:

Concentration of hydrogen ion, [H^+]=5.0118*10^{-6} M

Explanation:

pH is defined as the negative logarithm of hydrogen ion's concentration.

The lower the value of pH, the higher the acidic the solution is.

The formula for pH can be written as:

pH=-log[H^+]

Given,

pH of the saliva of Marco = 5.3

To calculate: Hydrogen ion concentration in the saliva

Thus, applying in the formula as:

pH=-log[H^+]

5.3=-log[H^+]

So,

log[H^+]=-5.3

[H^+]=10^{(-5.3)}

[H^+]=5.0118*10^{-6} M

8 0
4 years ago
In a solution, the ____________ is the substance that does the dissolving and the _____________ is the substance that is being d
Ivenika [448]

Answer:

soluble, solubility

i think its answer

5 0
3 years ago
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