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Bond [772]
3 years ago
10

2O POINTS AND BRAINLIEST!!! FAST ANSWER PLEASE!!!! I WILL FAIL THIS IF YOU DON'T HELP ME!!!!!!

Chemistry
2 answers:
Flauer [41]3 years ago
8 0
 <span>1. 1 molecule of C6H12O6(dextrose sugar), 2 molecles of c2h6o (ethyl alcohol), 2 molecules of Co2 

2. 48 hydrogen atoms </span>
Anna35 [415]3 years ago
8 0
The easy way to do this is to remember that the number of molecules is the big number at the very beginning which makes your answer:

__1__ molecule(s) of dextrose sugar yields __2__ molecule(s) of ethyl alcohol plus __2__ molecule(s) of carbon dioxide through the action of yeast. The small amount of alcohol evaporates during baking. __12__ hydrogen atoms are involved in this reaction.
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The combustion of hydrogen-oxygen mixtures is used to produce very high temperatures (ca. 2500 °C) needed for certain types of w
tangare [24]

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1360kJ are evolved

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When 1mole of H2 reacts with 1/2 moles O2 producing 1 mole of water and 241.8kJ.

To solve this question we need to find the limiting reactant knowing were added 90g of H2 and 90g of O2 as follows:

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<em>Moles O2 -Molar mass: 32g/mol-</em>

90g * (1mol / 32g) = 2.81moles

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As there are 45 moles, H2 is the excess reactant and O2 the limiting reactant.

As 1/2 moles O2 produce 241.8kJ, 2.81 moles will produce:

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6 0
2 years ago
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