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NikAS [45]
3 years ago
9

What volume will 25.0g ammonia occupy at stp

Chemistry
1 answer:
Slav-nsk [51]3 years ago
3 0

Answer:

The volume of 25 g O2 at STP is ~18 L.

Explanation:

can you mark me brainliest pls :)

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using the chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 4 mol of NaHCO3 and 8
Pavlova-9 [17]
Reaction is NaHCO3 + HCL = H2CO3 + NaCl
the ratios are 1:1 

the 8 moles of HCl are in excess

so if you use 4 moles of NaHCO3 then you will obtain 4 moles of carbonic acid

hope that helps
6 0
3 years ago
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The total momentum of a group of objects remains________ unless outside forces act on the group.
damaskus [11]

Answer:

<em><u>constant</u></em>

Explanation:

In consideration of the conservation principle of linear momentum

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3 years ago
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Taya2010 [7]
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3 years ago
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How many milliliters of nitrogen, N2, would have to be collected at 99.19 kPa and 28oC to have a sample containing 0.015 moles o
Semmy [17]

Answer:

378mL

Explanation:

The following data were obtained from the question:

Pressure (P) = 99.19 kPa

Temperature (T) = 28°C

Number of mole (n) = 0.015 mole

Volume (V) =...?

Next, we shall convert the pressure and temperature to appropriate units. This is illustrated below:

For Pressure:

101.325 KPa = 1 atm

Therefore, 99.19 kPa = 99.19/101.325 = 0.98 atm

For Temperature:

T(K) = T(°C) + 273

T(°C) = 28°C

T(K) = 28°C + 273 = 301K.

Next we shall determine the volume of N2. The volume of N2 can be obtained by using the ideal gas equation as shown below:

PV = nRT

Pressure (P) = 0.98 atm

Temperature (T) = 301K

Number of mole (n) = 0.015 mole

Gas constant (R) = 0.0821atm.L/Kmol.

Volume (V) =...?

0.98 x V = 0.015 x 0.0821 x 301

Divide both side by 0.98

V = (0.015 x 0.0821 x 301) /0.98

V = 0.378 L

Finally, we shall convert 0.378 L to millilitres (mL). This is illustrated below:

1L = 1000mL

Therefore, 0.378L = 0.378 x 1000 = 378mL

Therefore, the volume of N2 collected is 378mL

4 0
3 years ago
What is the composition of Gilsonite?
nekit [7.7K]

Answer:

Roughly C100 H140 N3 O

Explanation:

Gilsonite is a bituminous product that resembles shiny black obsidian.

It contains more than 100 elements.

Its mass composition varies but is approximately 84 % C, 10 % H, 3 % N, and 1 % O.

Its empirical formula is roughly C100 H140 N3 O.

3 0
3 years ago
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