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3 years ago

PLEASE HELP!! I'LL GIVE BRAINLIEST!! ( I put the other pic because i didn’t know if that was needed for those two questions)

Chemistry

2 answers:

-Dominant- [34]3 years ago

8 0

Answer:

1. The skater's kinetic energy decreases as he moves up the ramp. As the skater moves down the ramp, his potential energy decreases

2.Kinetic Energy is the energy of motion. As the skateboard rolls down the ramp it loses potential energy and gains kinetic energy. The total energy of the skateboarder remains constant.

nekit [7.7K]3 years ago

7 0

Answer:

The skater's kinetic energy decreases as he moves up the ramp. As the skater moves down the ramp, his potential energy decreases

Kinetic Energy is the energy of motion. As the skateboard rolls down the ramp it loses potential energy and gains kinetic energy. The total energy of the skateboarder remains constant.

Explanation:

hope this help

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A site in Pennsylvania receives a total annual deposition of 2.688 g/mof sulfate from fertilizer and acid rain. The ratio by mas

sertanlavr [38]

According to the statement

2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid

<h3>What is neutralization?</h3>

A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization or neutralization. In a water reaction, neutralization ensures that there is no excess of hydrogen or hydroxide ions in the solution.

<h3>According to the given information:</h3>

The equation of the neutralization reaction between H2SO4 and CaCO3.

CaCO3 + H2SO4 → CaSO4 + H2CO3

H2CO3 dissociate to water and carbon dioxide.

CaCO3 + H2SO4 → CaSO4 + H2O + CO2

Now solving for the mass of CaCO3 needed to neutralize the acid.

mass of CaCO3 = 9460 Kg H2SO4 × $\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}} \times \frac{1 \mathrm{~mol} \mathrm{H}_2 \mathrm{SO} 4}{98.1 \mathrm{gH}_2 \mathrm{SO}_4} \times \frac{1 \mathrm{~mol} \mathrm{CaCO}\left(\mathrm{O}_3\right.}{1 \mathrm{~mol} \mathrm{H}_2 \mathrm{SO}_4}$ $\times \frac{100.1 \mathrm{~g} \mathrm{CaCO}_3}{1 \mathrm{~mol} \mathrm{CaCO}_3} \times \frac{2.205 \mathrm{lb}}{1000 \mathrm{~g}}$

= 21284.56606

mass of CaCO3 = 2.12 x 10^4 lbs

2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid.

To know more about neutralization visit:

brainly.com/question/12498769

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4 0

1 year ago

Cracking the periodic table code why aren't the elements listed in alphabetical order answer key

finlep [7]

The elements in the periodice table are not listed in alphabetical order, because the arragement in rows (periods) and columns (groups or familes), in increasing order of atomic number (number of protons of the atoms) permits to explain similarities among the elements, trend in some properties, and even predict properties of unknown elements.

For example, the elements of the first group (family), called alkaline metals, all have 1 valence electron, have similar physical properties (ductibility, malleability, luster, thermal and electricity conductivity), react in similar way with water, show a trend in the atomic radii and in the ionization energy.

You can tell similar stories for other groups like, alkalyne earth metals, halogens and noble gases.

You can also tell trends in electroneativities, and atomic radii, for a row of elements, as per the order they are in the row.

So, the current array resulted very helpul for chemists to explain and predict the behavior and properties of the elements.

4 0

3 years ago

Read 2 more answers

Give a chemical equation for aerobic cellular respiration

Aleonysh [2.5K]

C6H12O + 6OC2 + 6H2O + energy

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3 years ago

The particle picture is best described as...

mixas84 [53]

Answer:

Both are pure substances and a compound

8 0

3 years ago

Calculate each of the following quantities. (a) Mass (g) of solute in 175.4 mL of 0.267 M calcium acetate WebAssign will check y

ss7ja [257]

Answer:

a) 7.40 grams

b) 0.213 M

c) 102 moles

Explanation:

(a) Mass (g) of solute in 175.4 mL of 0.267 M calcium acetate

Step 1: Data given

Volume = 175.4 mL = 0.1754 L

Molarity = 0.267 M

Molar mass = 158.17 g/mol

Step 2: Calculate moles

Moles = molarity * volume

Moles = 0.267 M * 0.1754 L

Moles = 0.0468 moles

Step 3: Calculate mass

Mass = 0.0468 moles * 158.17 g/mol

<u>Mass = 7.40 grams</u>

b) Molarity of 597 mL solution containing 21.1 g of potassium iodide

Step 1: Data given

Volume = 597 mL = 0.597 L

Mass = 21.1 grams

Molar mass KI = 166.0 g/mol

Step 2: Calculate moles KI

Moles KI = 21.1 grams / 166.0 g/mol

Moles KI = 0.127 moles

Step 3: Calculate molarity

Molarity = moles / volume

Molarity = 0.127 moles / 0.597 L

Molarity = 0.213 M

Step 1: Data given

Volume = 145.6 L

Molarity = 0.703 M

Step 2: Calculate moles

moles = molarity * volume

Moles = 0.703 M * 145.6 L

Moles = 102 moles

8 0

3 years ago